Question

Solve this system of linear equations. Separate

Answer 1

15x=-42-19y

• 15x+19y+42=0-(1)

3x=-54-19y

• 3x+19y+54=0--(2)

Subtract both

• 12x-12=0
• 12x=12
• x=1

Put in second

• 3(1)+19y+54=0
• 19y+57=0
• y=-3

So

• (x,y)=(1,-3)

Answer 2

Answer:

1, -3

Step-by-step explanation:

Question

Solve the system of linear equations:

• 15x = -42 - 19y
• 3x = -54 - 19y

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Solution

Subtract the equations to eliminate y:

     15x = -42 - 19y

-      3x = -54 - 19y

    ----------------------

    12x = 12

⇒ x = 12 ÷ 12

⇒ x = 1

Now substitute the found value of x into one of the equations and solve for y:

⇒ 15x = -42 - 19y

⇒ 15(1) = -42 - 19y

⇒ 15 = -42 - 19y

⇒ 19y = -42 - 15

⇒ 19y = -57

⇒ y = -57 ÷ 19

⇒ y = -3

Therefore, x = 1 and y = -3