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maw [93]
2 years ago
5

Solve this system of linear equations. Separate

Mathematics
2 answers:
AleksAgata [21]2 years ago
4 0

15x=-42-19y

  • 15x+19y+42=0-(1)

3x=-54-19y

  • 3x+19y+54=0--(2)

Subtract both

  • 12x-12=0
  • 12x=12
  • x=1

Put in second

  • 3(1)+19y+54=0
  • 19y+57=0
  • y=-3

So

  • (x,y)=(1,-3)
emmainna [20.7K]2 years ago
4 0

Answer:

1, -3

Step-by-step explanation:

<h3><u>Question</u></h3>

Solve the system of linear equations:

  • 15x = -42 - 19y
  • 3x = -54 - 19y

-------------------------------------------------------------------------------------

<h3><u>Solution</u></h3>

Subtract the equations to eliminate y:

     15x = -42 - 19y

-      3x = -54 - 19y

    ----------------------

    12x = 12

⇒ x = 12 ÷ 12

⇒ x = 1

Now substitute the found value of x into one of the equations and solve for y:

⇒ 15x = -42 - 19y

⇒ 15(1) = -42 - 19y

⇒ 15 = -42 - 19y

⇒ 19y = -42 - 15

⇒ 19y = -57

⇒ y = -57 ÷ 19

⇒ y = -3

Therefore, x = 1 and y = -3

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Pls help me on this.
bogdanovich [222]

9514 1404 393

Answer:

  domain: (-4, -2) ∪ [-1, 4]

  range: (-5, 3)

Step-by-step explanation:

<u>Domain</u>

The domain is the horizontal extent of the graph. Here, it is comprised of two intervals. The left interval is open, as the function is not defined for x-values of -4 or -2. That interval is (-4, -2). The right interval is closed, as the function is defined for both x=-1 and x=4. That interval is [-1, 4]. The domain is the union of these two intervals.

  D: (-4, -2) ∪ [-1, 4]

__

<u>Range</u>

The range is the vertical extent of the graph. The left portion of the graph has a range from -5 to 3, but neither of those values is included in it. That is, the range is an open interval: (-5, 3).

The right portion of the graph has a range from 1 to 2, including both of those values. This interval is already included in the interval (-5, 3), so only one interval is needed to describe the range:

  R: (-5, 3)

8 0
3 years ago
Write the solution to the given inequality in interval notation.
vladimir2022 [97]

Option D: (-\infty, 0) is the solution to the inequality in interval notation.

Explanation:

The number line shows the interval of numbers starting from 0 and goes on.

From the number line, it is obvious that the open circle at the point 0 indicates that we don't want to include the number 0.

Hence, in interval notation, we can write that the end values not to be included can be written with a round bracket ( )

Thus, the interval can be written as (-\infty, 0)

Hence, the solution to the inequality in interval notation is (-\infty, 0)

Therefore, Option D is the correct answer.

6 0
3 years ago
Pls help will give brainliest and 5star plssssss
ludmilkaskok [199]

2)

P(4,-4) -->(-4, 7)

4 - 8 = -4           -------->left 8

-4 + 11 = 7         -------->up 11

Answer: left 8;  up 11

3)

C(3,-1) , left 4 up 1

3 - 4 = -1    -------->left 4

-1 + 1 = 0   -------->up 1

a)

(x , y) -->(x - 4 , y +1)

C(3, -1) -->C'(-1 , 0)

b)

(x , y) --> (x - 4, y + 1); (-1 , 0)

7 0
3 years ago
What is the answer to this word problem??
AveGali [126]
Let’s use m for months
So,
1st service
10m + 20

1. 10 + 20 =30
2. 10x2=20+20=40
3.10x3=30+20=50
4.10x4=40+20=60
5.10x5=50+20=70

2nd service
11m + 15

1. 11+15=26
2. 11x2=22+15=37
3 11x3=33+15=48
4.11x4=44+15=59
5.11x5=55+15=70

So, the 5th month the services cost the same

Hope this helps! ;)

7 0
3 years ago
Benjamin correctly graphed the quadratic function y = -3x2 + 5. Which of these is true of Benjamin's graph? A. The graph of the
dmitriy555 [2]

Its C the graph has a maximum value at (0,5)

7 0
3 years ago
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