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ivanzaharov [21]
3 years ago
9

Please help me simplify these expressions

Mathematics
2 answers:
Stella [2.4K]3 years ago
7 0

Answer:

1. x^{11}     2. 10n^{9}   3.  6x^{10}

Step-by-step explanation:

1.   x^{11}

Imagine the expression is written like this:

(x)(x) *  (x)  * (x)(x)(x) * (x)(x)(x)(x)(x)

Simply add up the number of x's and have that number be the exponent.

There are 11 x's, so it will be x^{11}

2. 10n^{9}

Do the same as above, but this time remember that two negatives equal a positive.

10n^{9}

3. 6x^{10}

Again, two negatives equal a positive.

-3 x 2 x -1 = 6

Do the same as the above two.

6x^{10}

Archy [21]3 years ago
5 0

Answer:

Step-by-step explanation:

If base of variable is same, add the powers

1) x² * x * x³ * x⁵ = x²⁺¹⁺³⁺⁵ = x¹¹

2) -2n² * -n⁴ * 5n³ = (-2* -1*  5 ) *n²⁺⁴⁺³ = 10n⁹

3)-3x⁴ * 2x⁵ * - x = (-3 * 2 * -1)* x⁵⁺⁴⁺¹ = 6x¹⁰

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Answer:

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Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

In order to see the rule of formation, let's see the value (in $) for the first few years

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The <em>present value PV</em> is

\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

rounded to the nearest hundredth.

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