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3 years ago

WILL MARK BRAINLIEST FIRST CORRCET ANSWER

Mathematics

1 answer:

Kazeer [188]3 years ago

4 0

The Venn diagram of each situation is a diagrammatic way of representing what the situation stands for

<h3>How to make the Venn diagrams?</h3>

Diagram 1: A ∩ B ∩ C

This means that we shade all intersection points of the sets A, B and C

Diagram 2: (A ∩ B) ∪ C

This means that we shade the intersection points of the sets A and B and the whole of set C

Diagram 3: A ∩ (B ∪ C)

This means that we shade the where the set A intersects with the whole of sets B and C

Diagram 4: (A ∩ B) \ C

This means that we shade the intersection point of the sets A and B without shading any point on set C

Diagram 5: (A\B) ∪ (B\C) ∪ (A\C)

This means that we shade all set A without set B, all set B without set C and all set A without set C. In other words, we shade everything in the set without shading set C

See attachment for the diagrams

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What is the product?

fredd [130]

Answer:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

Step-by-step explanation:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4 can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace 4k +2 by 2 (2k + 1)

and

k² - 4 by (k-2)(k+2) in the expression given

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

$\frac{2(2k+ 1)}{(k-2)(k+2)}$ × $\frac{k-2}{2k+1}$

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;

$\frac{2}{k + 2}$

Therefore, $\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

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Virty [35]

Answer:

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1/5 of what equals 4?

MaRussiya [10]

Answer:

Step-by-step explanation:

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There was a blizzard. Snow was falling at the rate of 4 1/2 inches per hour. If the snow keeps acclimating how long will 5 feet

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