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Serhud [2]
3 years ago
6

What is the perimeter and area of the figure?

Mathematics
1 answer:
Rudiy273 years ago
7 0

Perimeter is the sum of all outside dimensions:

5 + 3 + 1 + 2 + 4 + 5 = 20cm

Area = (5 x 5) - (2*1) = 25 - 2 = 23 cm^2

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NEED HELP NOW 50 POINTS!!!!!!!!!
puteri [66]
1st. is definitely 150.
2nd. is a i think
3rd. is 100 

8 0
3 years ago
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What means the same as 6 × 5? <br> A.6^5 <br> B.5 + 5 + 5 + 5 + 5 <br> C.6 + 6 + 6 + 6 + 6
skelet666 [1.2K]

Here is your answer:

In order to find your answer we will have to solve each option separately to see which one equals 6 × 5.

  • 6^5 = 6\times6\times6\times6\times 6 <---- Not the answer
  • 5 + 5 + 5 + 5 + 5 = 25 <----- Not the answer
  • 6 + 6 + 6 + 6 + 6 = 35 <---- Your answer

Therefore your answer is option C "6 + 6 + 6 + 6 + 6 ."

Hope this helps!

8 0
3 years ago
Read 2 more answers
Can you tell how many students got allowances of $15? Explain.
neonofarm [45]
5 because it says 11-16 which is one number before 15. dollars
5 0
3 years ago
One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
Read 2 more answers
Jasmine has only $46.50 to spend at forever 21. She wants to buy a shirt that costs $19, including tax, and some bracelets that
ivanzaharov [21]
46.50 - 19 = 5.50x

We get the 46.50 from her budget and the 19 from the shirt she wants to buy. If we subtract 19 from 46.50, we'll get the amount of money Jasmine can spend on bracelets.

46.50 - 19 = 27.50

She has $27.50 to spend on bracelets. Now, we divide that by 5.50 (the price of a bracelet) to see how many she can buy.

27.50 ÷ 5.50 = 5

Jasmine can buy 5 bracelets.

Hope this helps!
4 0
3 years ago
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