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4 years ago

A goat enclosure is in the shape of a right triangle. One leg of the enclosure is built against the side of the barn. The other

Mathematics

2 answers:

Sonbull [250]4 years ago

4 0

Answer:

The lengths are

8 + 8[root]3 , 12 + 8[root]3 and 20 + 8[root]3.

Step-by-step explanation:

Let the side against the barn be xft

We were told that the adjacent side is 4ft more than the side against the barn. This means it has a length of (x + 4)ft.

Lastly, we are told that the hypotenuse is 8ft longer than the side along the barn I.e (x + 4 + 8)ft = ( x + 12)ft.

Since the three lengths form a triangle, the square of the hypotenuse equals the square of the adjacent side plus the square of the opposite side. This is the pythagoras' theorem.

Mathematically, this can be written as follows:

(x + 12)^2 = x^2 + (x + 4)^2

This yields x^2 + 24x + 144 = x^2 + x^2 + 8x + 16

x^2 + 24x + 144 = 2x^2 + 8x + 16

Rearranging this will yield:

x^2 - 16x - 128 = 0

Using the quadratic formula yields the following values for x :

8 - 8[root]3 and 8 + 8[root 3]

Since the first is negative, we discard it and the only correct value of x is 8 + 8[root]3

Now the other length is 12 + 8[root]3 and 20 + 8[root]3.

eimsori [14]4 years ago

4 0

Answer:

20,16,12

Step-by-step explanation:

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3 years ago

The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml

irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63$

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$