6 - 4x = (3 - x)
Subtract 6 from both sides, as well as adding x to both sides.
-4x + x = 3 - 6
Add like terms.
-3x = -3
Divide both sides by -3.
x = 1
So, your answer is c) All real, numbers because all of the other answer choices are wrong.
We know this because a) and b) are incorrect. To know if they are incorrect, you just plug in the numbers. When 2 and -2 are plugged into the equation, it is incorrect. So, you solve the equation, and you now know that it is not D) because there is a solution.
So, once again, your answer is C.
~Hope I helped!~
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Let D= {4,7,9} , let E {4,6,7,8}, and let F={3,5,6,7,9}a) find the D U Eb) find the E n F
Juli2301 [7.4K]
the given sets are,
D= {4,7,9} , let E {4,6,7,8}, and let F={3,5,6,7,9}
now,
D U E = { 4 , 6, 7 , 8, 9}
and'
E intersection F = E n F = {6 , 7)
thus, the answer is
D U E = { 4 , 6, 7 , 8, 9} and
E n F = {6 , 7)
Answer:
B
Step-by-step explanation:
Let the nickels = x
Let the dimes = y
You don't know the total value of either. Nor do you know the total number of either.
You only know the total value of both together.
7.80 added to anything makes it bigger than 7.80 A is wrong.
y cannot be alone it should be multiplied by 0.5 C is wrong
D is wrong for the same reason A is
B is the correct answer. That is the way you write the problem
Number of Coins and value on one side. Total on the other.
EQ. 1: x + y = 8
EQ. 2: 4x-y = 7
Rewrite EQ. 1 as EQ. 3: x = 8-y
Replace x in EQ.2 with EQ. 3:
4(8-y) - y = 7
Use the distributive property:
32 - 4y - y = 7
Combine like terms:
32 - 5y = 7
Subtract 32 from each side:
-5y = -25
Divide both sides by -5
y = -25 / -5
y = 5
Now replace y with 5 in EQ. 3 to solve for X:
x = 8-5
x = 3
The point of intersection is X = 3, Y = 5, which is written as (3,5)
