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alexandr402 [8]
3 years ago
12

Rita is adding 3 + (–8) + 1. She rewrites the expression as 3 + (–1) + 8. What is Rita’s error?

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0

Answer:

Rita made the 1 negative and the 8 positive

Step-by-step explanation:

we have

3+(-8)+1

eliminate the parenthesis

3+(-8)+1=3-8+1=-4 ----> in the expression the 1 is positive and the 8 is negative

Rita made the 1 negative and the 8 positive

8090 [49]3 years ago
4 0
The original sum has (+3) + (-8) + (+1), whereas in her rewritten version, the 1 is negative and the 8 is positive, which is incorrect. If we were answer the first, it would equal -4, but if we were to answer the second, it would equal 10. I hope this helps!
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2(× - 2)=4× - 6(× - 2)​
Bond [772]

Hey there!

Assuming you meant: "\bold{2(x-2=4x-6(x-2)}"

If so follow these steps

  • \bold{Distribute\downarrow}
  • \bold{2(x)+2(-2)=4(x)+(-6)x+(-6))(-2)}
  • \bold{2(x)=2x}
  • \bold{2(-2)=-4}
  • \bold{4x=4x}
  • \bold{-6(x)=-6x}
  • \bold{(-6)(-2)=12}
  • We get: \bold{2x-4=(4x+(-6x))+12}[/tex[tex]\bold{Combine\downarrow}
  • All the x-values are one and the regular numbers are one
  • We get: \bold{2x-4=-2x+12}
  • \bold{Add} by \bold{2x} on your sides
  • \bold{2x-4+2x=-2x+12+4}
  • We now get: \bold{4x-4=12}
  • \bold{Add} by \bold{4} on each of your sides
  • \bold{4x-4+4=12+4}
  • We get: \bold{4x=16}
  • \bold{Divide} by \bold{4} on each of your sides
  • \bold{\frac{4x}{4}=\frac{16}{4}}
  • \boxed{\boxed{\bold{Answer:x=4}}}\checkmark

Good luck on your assignment and enjoy your day

~\frak{LoveYourselfFirst:)}

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