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alexandr402 [8]
3 years ago
12

Rita is adding 3 + (–8) + 1. She rewrites the expression as 3 + (–1) + 8. What is Rita’s error?

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0

Answer:

Rita made the 1 negative and the 8 positive

Step-by-step explanation:

we have

3+(-8)+1

eliminate the parenthesis

3+(-8)+1=3-8+1=-4 ----> in the expression the 1 is positive and the 8 is negative

Rita made the 1 negative and the 8 positive

8090 [49]3 years ago
4 0
The original sum has (+3) + (-8) + (+1), whereas in her rewritten version, the 1 is negative and the 8 is positive, which is incorrect. If we were answer the first, it would equal -4, but if we were to answer the second, it would equal 10. I hope this helps!
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The reason that it's represented as 12x + 10 is because there is a flat fee of $10 when you sign up. From then on afterward, every month you pay $12.

In this equation, the variable 'y' represents the total cost, while 'x' represents the number of months this service was in use.

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3 years ago
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Answer:

Step-by-step explanation:

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2 years ago
in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

the proportion is

p = 154/200 = 0.77

<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

<em>Mean </em>

p = 0.77

<em>Standard deviation </em>

\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298

The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

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icang [17]

Answer:

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Step-by-step explanation:

Hope it helps

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