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Aliun [14]
2 years ago
7

What does the solution to a system of equations mean?

Mathematics
1 answer:
frozen [14]2 years ago
5 0

Answer:

The solution to a system of equations means the point must work. In both equations in the system, if you are asked if a point is a solution to an equation, you replace the variables with the given values and see if the two sides of the equation is equal "so is a solution"

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Cosx=4/5 what is sin2x cos2x and tan2x
earnstyle [38]

Answer:

-24/5

Step-by-step explanation:

The solution to the problem is as follows:

cscx < 0 means 1/sinx < 0, or sinx < 0.  

sinx = -3/5 because you're dealing with a 3-4-5 triangle, and we established

sinx is negative.  

sin2x = 2sinxcosx = 2*-3/5*4/5 = -24/25  

cos(2x) = cos^2(x) - sin^2(x) = 16/25 - 9/25 = 5/25 = 1/5  

tan2x = sin2x / cos2x = -24/5

4 0
3 years ago
Si yo tengo una canasta llena de mangos y piñas, de las cuales hay 30
skelet666 [1.2K]

Respuesta: Es más probable sacar un mango.

Explicación:

La probabilidad se refiere a la posibilidad de que un evento occura y no otro. En el caso que se describe, la probabilidad de sacar cada fruta puede ser calculada dividiendo el total de cada fruta en el número de frutas totales:

Probabilidad de sacar un mango:

\frac{cantidad de mangos}{cantidad de frutas en la canasta} =  \frac{30}{50}  =0.6

Probabilidad de sacar una piña:

\frac{cantidad de pinas}{cantidad de frutas en la canasta} = \frac{20}{50} = 0.4

De acuerdo a lo anterior la probabilidad de sacar un mango es de 0.6 o de 60% (multiplica la probabilidad por 100 para saber su equivalente en porcentaje), mientras que la probabilidad de sacar un mango es de 0.4 o 40% lo cual es mucho más bajo. Es decir que es más probable sacar un mango.

7 0
3 years ago
The Murphy family is on a road trip. On the first day, they traveled 30% of their total distance. On the second day, they travel
Otrada [13]

Answer:

5/12

Step-by-step explanation:

Total distance travelled = 30% + 1/4

To add these numbers, convert 30% to fraction

30% = 1/3

1/3 + 1/4 = 7/12

Remaining distance = 1 - 7/12 = 5/12

7 0
3 years ago
Positive numbers must have the positive sign (+) in front of them.<br><br><br> True False
torisob [31]
No
A number that doesn’t have any sign in front of it is naturally considered as positive.
But, negative numbers should have a negative sign in front of them though.
3 0
4 years ago
Read 2 more answers
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
4 years ago
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