Hi there! Use the following identities below to help with your problem.

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

As we know, sec²θ = 1/cos²θ.

And thus,

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

Answer
- sinθ = -4sqrt(17)/17 or A choice.
Answer:
Step-by-step explanation:
18*18 = 324
So 18 is the closest integer to 
Answer:
(8, -1)
Step-by-step explanation:
the solution is where they intersect. (x, y) and x is 8 while y is -1
First graph it
#1
Maximum height is the y coordinate of vertex
Max height
#2
Time is the x coordinate of vertex
#3

x intercepts are the solutions
Take it positive
#4
put in function
- y=-16(1)+64+80=-16+144=128ft