Answer:
no because 3/20 is eguivilent to 0.15 whitch is half of 0.3
I think c.
bc when u add it up and stuff
Answer:
The 39th triangle number is 780
<span>Ok so consider 100 divided by 11. remainder here is 1. Now consider the remainder when 100×100 is divided by 11. consider that you have one hundred hundreds, and each of them have a remainder of 1 when divided by 11. So, go through each of your hundred hundreds and divide it by 11, leaving remainder 1. Then collect up your remainders into a single hundred, and divide it by 11, leaving a remainder of 1. This process can be extended to dividing 100x100x100 by 11, and indeed, to dividing any power of 100 by 11.</span>
You can see the trapezoid in the attached picture.
The data given in the problem are:
KF = 10
LK // MF
A(KLMF) = A(FMN)
We know that KLMF is a parallelogram because:
LM // KF (bases of the trapezoid)
LK // MF (hypothesis).
The area of a parallelogram is given by the formula:
A(KLMF) = b × h
= KF <span>× h</span>
= 10 × h
The area of a triangle is given by the formula:
<span>A(FMN) = (b × h) / 2
= (FN </span>× h) / 2
The problem states that the two areas are congruent, therefore:
A(KLMF) = <span>A(FMN)
</span>10 × h = FN <span>× h / 2
10 = FN </span><span>/ 2
FN = 20
Therefore we can calculate:
KN = KF + FN = 10 + 20 = 30
Hence, KN is
30 units long.</span>