Ok so consider 100 divided by 11. remainder here is 1. Now consider the remainder when 100×100 is divided by 11. consider that you have one hundred hundreds, and each of them have a remainder of 1 when divided by 11. So, go through each of your hundred hundreds and divide it by 11, leaving remainder 1. Then collect up your remainders into a single hundred, and divide it by 11, leaving a remainder of 1. This process can be extended to dividing 100x100x100 by 11, and indeed, to dividing any power of 100 by 11.

3 0

3 years ago

Given: KLMN is a trapezoid, KF =10 MF ║ LK AKLMF = AFMN Find: KN

Nimfa-mama [501]

You can see the trapezoid in the attached picture.

The data given in the problem are:
KF = 10
LK // MF
A(KLMF) = A(FMN)

We know that KLMF is a parallelogram because:
LM // KF (bases of the trapezoid)
LK // MF (hypothesis).
The area of a parallelogram is given by the formula:
A(KLMF) = b × h
 = KF × h
 = 10 × h

The area of a triangle is given by the formula:
A(FMN) = (b × h) / 2
 = (FN × h) / 2

The problem states that the two areas are congruent, therefore:
A(KLMF) = A(FMN)
10 × h = FN × h / 2
10 = FN / 2
FN = 20

Therefore we can calculate:
KN = KF + FN = 10 + 20 = 30

Hence, KN is 30 units long.

3 0

3 years ago