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Allisa [31]
2 years ago
6

For the inverse variation equation xy = k, what is the constant of variation, k, when x = 7 and y = 3? three-sevenths seven-thir

ds 10 21
Mathematics
1 answer:
vova2212 [387]2 years ago
4 0

The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k can be written as,

xy=k\\\\(7) \times (3 ) =k\\\\k= 21

Hence, the value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.

Learn more about Equation:

brainly.com/question/2263981

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Luis wants to buy a skateboard that usually sells for $79.08. All merchandise is discounted by 12%. What is the total cost of th
FrozenT [24]

Answer:

$74.96

Step-by-step explanation:

$79.80 × 0.12 = 9.576 (discount)

$79.80 - $9.576 = $70.224

$70.224 × 0.0675 = 4.74012 (add for sales tax)

$70.224 + $4.74012 = $74.96412

8 0
3 years ago
Last year at a certain high school, there were 75 boys on the honor roll and 50 girls on the honor roll. This year, the number o
Fantom [35]

In linear equation, 15.2% did the total number of students on the honor roll decrease.

What in mathematics is a linear equation?

  • A linear equation is a first-order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept.
  • Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

50 × 24% = 12

50 × 14%= 7

12+ 7 = 19

50+75 = 125

19 ÷125= 15.2%

Learn more about linear equation

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#SPJ4

8 0
1 year ago
4 more than 4 times x is 45
balu736 [363]
4 more than 4 times x is 45 the answer will be x=41/4
3 0
3 years ago
Read 2 more answers
Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1
Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

f(x) = x^3+6x-5

For x = 0. the value of the expression is:

f(0) = 0^3+0-5\\f(0) = -5

For x = 1, the value of the expression is:

f(1) = 1^3+6-5\\f(1)=2

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0
3 years ago
Evaluate f(x) = –x2 – 4 for x = –3.
melisa1 [442]
The answer to your problem is 2

6 0
3 years ago
Read 2 more answers
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