Answer:
P = (21.4a+36.6) cm
Step-by-step explanation:
Given that,
The width of a rectangle, b = (6.9a+8.5) cm
The length of a rectangle, l = (3.8a+9.8) cm
We need to find the perimeter of the rectangle. Perimeter is the sum of all sides. So,
P = 2(l+b)
Put all the values,
P = 2(6.9a+8.5+3.8a+9.8)
= 2(6.9a+3.8a+8.5+9.8)
= 2(10.7
a+18.3)
= (21.4a+36.6)
So, the perimeter of the rectangle is (21.4a+36.6) cm.
X is the easy one to solve here. A triangle must have 180 degrees. Add 90 to 38 and subtract that value from 180. This results in x = 52 Degrees. Y is a little bit more difficult. Because The two lines are parallel, Angle CDB is equal to the angle just above y-12. That angle is equal to x, in other words. This angle and y-12 must equal 180 when they are added together, as this is the value for degrees of a line. So, 180= (y-12) + 52. Just solve this algebraically, and is should result in y = 140 degrees.
Tldr: y = 140, x= 52
Answer:
I'm not even lying, it's none of them ;-;
btw if you want, can you give me brainliest :((
Recall your d = rt, distance = rate * time
so... let's say, the plane's speed in still air is "p", and the speed of the wind is "w".
when the plane is travelling with the wind over those 1000 miles, is really not going "p" fast, is going " p + w " fast, since it's going with the wind.
now, when the plane is travelling against the wind, is not going "p" fast either, is going " p - w " fast, since the wind is subtracting speed from it.
bearing in mind he cover the 1000 miles as well as the 880 miles in 2 hrs each way.
![\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ \textit{with the wind}&1000&p+w&2\\ \textit{against the wind}&880&p-w&2 \end{array} \\\\\\ \begin{cases} 1000=2(p+w)\\ \qquad 500=p+w\\ \qquad 500-p=\boxed{w}\\ 880=2(p-w)\\ ----------\\ \frac{880}{2}=p-w\\ 440=p-\left( \boxed{ 500-p }\right) \end{cases} \\\\\\ 940=2p\implies \cfrac{940}{2}=p\implies 470=p](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26distance%26rate%26time%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ctextit%7Bwith%20the%20wind%7D%261000%26p%2Bw%262%5C%5C%0A%5Ctextit%7Bagainst%20the%20wind%7D%26880%26p-w%262%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cbegin%7Bcases%7D%0A1000%3D2%28p%2Bw%29%5C%5C%0A%5Cqquad%20500%3Dp%2Bw%5C%5C%0A%5Cqquad%20500-p%3D%5Cboxed%7Bw%7D%5C%5C%0A880%3D2%28p-w%29%5C%5C%0A----------%5C%5C%0A%5Cfrac%7B880%7D%7B2%7D%3Dp-w%5C%5C%0A440%3Dp-%5Cleft%28%20%5Cboxed%7B%20500-p%20%7D%5Cright%29%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A940%3D2p%5Cimplies%20%5Ccfrac%7B940%7D%7B2%7D%3Dp%5Cimplies%20470%3Dp)
what's the speed of the wind? well, 500 - p = w.
Answer:
F(2x+3) = 12/(2x+3) +1/2
Step-by-step explanation:
Put the argument of the function where the variable is. You can simplify if you want, but the original function definition is not simplified, so we assume it is not required.
F(x) = 12/x + 1/2
Put (2x+3) where x is:
F(2x+3) = 12/(2x+3) + 1/2
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<em>Comment on the function</em>
If you intend f(x) = 12/(x +1/2), then you would do the same thing: put (2x+3) where x is. In this case, you could combine the +3 and the +1/2, if you want.
... F(2x+3) = 12/((2x+3) +1/2) = 12/(2x +3.5)