The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:

Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
Learn more about hypothesis from here brainly.com/question/14783359
#SPJ4
Answer : -6
The common difference of a sequence is the value that changes every time the sequence continues.
In your sequence it is seen that 6 is subtracted from each term in order to get to the next in the sequence.
There are many like
1(10)+10-1=19
18+1=19
30-11=19
15+4=19
Hope this help!!