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777dan777 [17]
2 years ago
5

Bag contains 4 red marbles, 2 blue marbles, 1 purple

Mathematics
1 answer:
GaryK [48]2 years ago
6 0

Answer:

432

Step-by-step explanation:

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Concider the graph of the polynomial function p(x)=(x-1)(x+2)(x+5)
yulyashka [42]
I need to see the horse??
4 0
3 years ago
********PLEASE HELP ****** DVD players are going out of fashion in the modern era. If 400,000 DVD players were sold this year an
abruzzese [7]
So 400,000 DVD sales with a 31% decline means in the 1st year following, there will be a decline of 124,000 DVDs sold. So we need to take 400,000 - 124,000, which equals a starting point for year two is 276,000 DVDs.

So a 31% decline on 276,000 = 85,560. So we need to subtract that from 85,560 from 276,000 which is 190,440. So at the end of the second year, DVD sales were only 190,440.  That's also out starting point of the 3rd year. 

So 31% of 190,440 equals 59,036.4 for the third year of DVD sales. So we need to subtract 59,036.4 from out third year starting point of 190,440, which equals 131,403.6, but since you can't have parts of DVDs, we'll round the decimal point fraction to a whole number to end up with 131,404 DVDs sold in year three.

So after three years of a 31% yearly decline in DVD sales you end up with DVD sales are 131,404














3 0
4 years ago
Read 2 more answers
Q12 A driver sees this speed limit sign in France. The speed is in kilometres per hour
olga nikolaevna [1]

Answer:

Step-by-step explanation: idk

7 0
4 years ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
4 years ago
How would I do this?
Lelu [443]
I'm not sure about part B, but part A will have the answer "if Ron eats lunch today, then he will drink a glass of milk" (without quotes of course)

The idea is that we have these arguments in symbolic form
P = Ron eats lunch today
Q = Ron eats a sandwich
R = Ron will drink a glass of milk

The format is 
"If P then Q" ----> "if Q then R"  so therefore "If P then R"

We see that P leads to Q, then Q leads to R. So overall P leads to R. We connect them as a chain of sorts. We can skip over Q since we know the first point will lead to the last. Think of it as a shortcut of sorts.
8 0
3 years ago
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