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2 years ago

How may this problem be checked?

Mathematics

1 answer:

topjm [15]2 years ago

4 0

It can be checked by multiplying the divisor 32 by the quotient 74

You can use pencil and paper to multiply, or a calculator

32*74 = 2368

We're 8 short of the goal of 2376, but notice how the remainder is 8. This is the amount to add on so we get to the goal of 2376

In other words,

32*74 + 8 = 2368+8 = 2376

You can think of it like having 2376 cookies and 32 friends. Each friend will get 74 cookies, and there will be 8 left over.

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Can you translate the measurements to (cups, teaspoons, tablespoons etc.)

Alex777 [14]

Answer:

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Hope this helps!!

Have A Blessed Day <333

4 0

3 years ago

To join a local square dancing group, Jan has to pay a $100 sign-up fee plus $25 dollars per month. Write an equation for the co

NemiM [27]

Answer:

y = 25x+100

Step-by-step explanation: You are paying 25$ times how many months he stayed there, plus a 100 dollar sign up fee, so y = 25 dollars per month, plus 100 dollars.

4 0

3 years ago

Find the missing measure if a and b are the legs of the right triangle and c is the hypotenuse, with a = 11 and c =18.

never [62]

Answer:

$\sqrt{203}$

Step-by-step explanation:

1. $11^{2} + b^{2} = 18^{2}$

2. $b^{2} =203$

3. b = $\sqrt{203}$

Can't be simplified.

3 0

3 years ago

Read 2 more answers

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago

Identify the type of conic section that is represented by the equation y^2- 1 = 4(x-7). DUE IN 2 HOURS, will give BRAINLIEST! A.

Elenna [48]

Answer:

Solution : Parabola

Step-by-step explanation:

As you can see only one variable is square in this situation, so it can only be a parabola. We can prove that it is a parabola however by converting it into standard form (x - h)^2 + (y - k)^2.

$y^2-1=4\left(x-7\right) = y^2-1=4\left(x-7\right)$

Respectively it's properties would be as follows,

$\left(h,\:k\right)=\left(\frac{27}{4},\:0\right),\:p=1$

8 0

3 years ago