Part a.
<span>The perimeter formula is: </span>
P = 2w + 2LYour answer for part A is
P = 2w + 2LPart b.
They tell us in part b, that:
w = 6L + 20
Substitute that into what we got for part a.
P = 2(6L + 20) + 2L
P = 12L + 40 + 2L
P = 14L + 40Your answer for partb is
P = 14L + 40Part c.
So we take what we got from part b, and solve for L.
P = 14L + 40
14L = P - 40
![L = \boxed{\frac{P-40}{14}}](https://tex.z-dn.net/?f=L%20%3D%20%5Cboxed%7B%5Cfrac%7BP-40%7D%7B14%7D%7D)
That is your answer for part 3 ^
part d.
Plug in w = 32 into what we first got in part b.
w = 6L + 20
32 = 6L + 20
6L = 12
L = 2Your answer for part d is
L = 2<span>:D</span>