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faltersainse [42]
2 years ago
15

Please help quick you need​

Mathematics
1 answer:
marysya [2.9K]2 years ago
6 0

Answer:

Box 2

Step-by-step explanation:

Box 1: 2x3x2=4x3=12

Box 2: 2x3x1=6x1=6

Box 3: 2x3x4=6x4=24

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Alexxandr [17]
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical. 
First, lets factor 8:
8=2 ^{3}
Now we can divide the power of the term, 3, by the index of the radical 2:
\frac{3}{2} = 1 with a remainder of 1
Next, lets do the same for our second term x^{7}:
\frac{7}{2} = 3 with a remainder of 1
Again, lets do the same for our third term y^{8}:
\frac{8}{2} =4 with no remainder, so this term will come out completely.

Finally, lets take our terms out of the radical:
\sqrt{8x^{7} y^{8}  }= \sqrt{ 2^{3} x^{7} y^{8}   }  =2 x^{3}  y^{4}  \sqrt{2x}

We can conclude that the correct answer is the third one. 

4 0
3 years ago
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Help! will<br> mark brainliest answer
drek231 [11]

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4 0
3 years ago
Simplify this expression HELP ASAP
Sergio039 [100]

Answer:

B

Step-by-step explanation:

Noting the following rule of radicals

\sqrt{a} × \sqrt{b} = \sqrt{ab}

Given

(\sqrt{2} + \sqrt{3})( \sqrt{5} - \sqrt{7} )

Each term in the second factor is multiplied by each term in the first factor

= \sqrt{2}(\sqrt{5} - \sqrt{7}) + \sqrt{3}(\sqrt{5} - \sqrt{7}) ← distribute parenthesis

= \sqrt{10} - \sqrt{14} + \sqrt{15} - \sqrt{21}

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Option b 10.44 ...........
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