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olchik [2.2K]
3 years ago
7

Can anyone please help me with these

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0

Answer: Natural/Counting = 1, 0, 6, 3,

Whole = 1234, 135

Integers = -42,260, -97

Rational = 0.5432, 14.4, 6.2, 6.5892,

-14.4, 7.7777777, -13.574,

3.14, 0.4, 6.2, 0.4, 0.34,

12/6, -8/4, -10/5, -3/4, -3/8,

3/7, -4/8, 6/2, -8/4

Irrational = √34, -√34, -√ 36, 2π, √81,

√300, √1, π.

;Hope this Helped with both Pages:)

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lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
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The midpoint A' is
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B) The slope of the line between (x1, y1) and (x2, y2) is given by
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C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
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D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
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