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Nesterboy [21]
3 years ago
15

Given:In quadrilateral WXYZ , WY and XZ bisect each other at point A. Prove: Quadrilateral WXYZ is a parallelogram.

Mathematics
2 answers:
aleksley [76]3 years ago
7 0
These bisectors intersect each-other at 90 degrees. And it means that they are perpendicular. Since they are perpendicular, we find that there 4 congruent triangles and XY is parallel to WZ and WX is parallel to YZ. Additionally, opposite angles are equal. These two latter findings are the characteristics of the parallelogram.   
FromTheMoon [43]3 years ago
5 0

The figure is not necessarily a parallelogram because only one diagonal is bisected and only one pair of sides is congruent.

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nadezda [96]

Answer:

1 \frac{7}{12}

3 \frac{19}{24}

8 \frac{3}{10}

5 \frac{1}{7}

5 \frac{5}{12}

3 \frac{11}{15}

Step-by-step explanation:

To add or subtract you need to make the denominator the same. To do this you need to find the least common multiple.

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Answer:

SSS similarity

Step-by-step explanation:

From the smaller triangle to the larger triangle, the ratio of each pair of corresponding sides is 2.

4 0
2 years ago
Simplify: 2y^2/ 4y^4 • 2y^3<br><br> A) xy^2/16<br> B) 1/y^6<br> C) y^3/6<br> D) 1/ 4y^5
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3 years ago
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Answer:

1240.4 mm²

Step-by-step explanation:

SA of Pentagonal pyramid:

(as)(5/2) + (sl)(5/2)

↑ ↑

base area lateral area

_____________________

a: apothem (in-radius) length, s: side length.

l: slant height.

______________________

Since we are already given the base area which is 440.4 mm². All we need to do is find the lateral area and add both areas together.

Given that the triangular face of the lateral part has a side/base length of 16mm, and a 20mm slant height.

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With this information the surface area is:

(16)(20)(5/2)mm + (440.4 mm²) →

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3 years ago
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