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qwelly [4]
3 years ago
10

What is the area of a triangular prism?

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

14! i think :D

Step-by-step explanation:

im probly worngg TvT

You might be interested in
What is the 2nd equvilent fraction to 1/2​
zhuklara [117]

Answer:

The 2nd equivalent fraction to 1/2 is 2/4

Step-by-step explanation:

The 2nd equivalent fraction of 1/2 is obtained by multiplying 1/2 by 2/2.

2nd equivalent fraction = 1/2 × 2/2 = 2/4

5 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!!
Blizzard [7]
Ts option A

cos C = (b - x) / a
a cos C = b - x

x = b - a cosC
3 0
3 years ago
PLEASE HELP ME!!!! WILL REWARD BRAINLIEST!!!!!
Sergeu [11.5K]

Answer:

-4 and -2.

Step-by-step explanation:

First of all,... OH MAN,... that is serious brain twisting logic (if you can call it logic) and to be fair I had to ask a math expert person I'm acquainted with,... cause I didn't know either,... so nothing to be ashamed about,...

If we let 2x equal the lesser of the two consecutive EVEN integers, and we let y equal 2x+2 be the greater of the two consecutive EVEN integers,

(For example, this is like x = 1, so 2x=2, y=4  or  x=7, so 2x=14 and y=16, we add 2 to the lesser even integer to get the next CONSECUTIVE even integer.)

 

This, y=2x+2,  is one of the equations we need.  To get the other,

 "Four times the lesser (4*2x) is (=)  12 less (-12) than twice the greater (2y)."

Doing it all in math, we get:

4(2x) = 2y - 12

This simplifies to:

8x = 2y - 12

And using the first equation (y=2x+2) we can substitute "2x+2" in for "y"  

8x = 2(2x + 2) - 12

Simplify the right side by first distributing:

8x = 4x + 4 - 12

Combine like terms on the right.

8x = 4x - 8

Subtract 4x from both sides

4x = -8

Divide both sides by 4

x= -2

Remember, our lesser even integer is 2x, so the lesser integer is 2*(-2)= -4, the greater is (-4)+2= -2.

Final answer:  The two consecutive even integers are -4 and -2.

To be even more fair I don't fully understand this completely either,... he explained it to me and I and <em>getting</em> it,... so anyway,... Hope it helps, and

Chow,...!

5 0
3 years ago
How many $10$-digit numbers are there, such that the sum of the digits is divisible by $2$?
navik [9.2K]

Complete question is;

How many 10 - digit numbers are there, such that the sum of the digits is divisible by 2?

Answer:

There are 4500000000 ten digit numbers whose sum is divisible by 2.

Step-by-step explanation:

Since we are dealing with 10 digit numbers, the first 10 digit number whose sum is divisible by 2 is; 1000000001.

While the last 10 digit number whose sum is divisible by 2 is 9999999999.

Now,to find how many 10 digit numbers whose sum are divisible by 2, we will simply divide the difference of both numbers by 2 and then add 1 to the answer. This is because subtracting the minimum from the maximum gives us the number of 10 digit numbers we have. Then dividing by 2 gives the number of ten digit numbers with sum divisible by 2 in between. Then adding 1 to the result to cover the number not included gives;

((9999999999 - 1000000001)/2) + 1 = 4500000000

7 0
3 years ago
Plz let me know if yes or no, and plz explain!!!
damaskus [11]

Answer:

Yes

Step-by-step explanation:

Because they are reflecting over a x intercept

7 0
3 years ago
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