Area of a square = length²
A = x²
16 = x²; x = 4
dA/dx = 2x cm²/s
dx/dt = 6 cm/s
Using chain rule:
dA/dt = dA/dx * dx/dt
dA/dt = 2x * 6
dA/dt = 12x
At x = 4,
dA/dt = 12(4) = 48 cm²/s
Answer:
Step-by-step explanation:
Step 1: Flip the equation.
Step 2: Subtract D from both sides.
Step 3: Divide both sides by Dr.
Answer:

Step-by-step explanation:
Given that,
The base of a triangle = 2 km
The perpendicular height of the triangle = 
We need to find the value of x. It is the Hypotenuse of the triangle. It can be solved as :

So, the value of x is equal to
.
Answer:
The equation for the trend line would be y = -1/100x + 25
Step-by-step explanation:
In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.
m(slope) = (y2 - y1)/(x2 - x1)
m = (0 - 25)/(2500 - 5)
m = -25/2500
m = -1/100
Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.
y = mx + b
y = -1/100x + 25
It would be - 1.75. Hope it helps! :)