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notka56 [123]
3 years ago
8

What is the 2nd equvilent fraction to 1/2​

Mathematics
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

The 2nd equivalent fraction to 1/2 is 2/4

Step-by-step explanation:

The 2nd equivalent fraction of 1/2 is obtained by multiplying 1/2 by 2/2.

2nd equivalent fraction = 1/2 × 2/2 = 2/4

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On a number line what is the distance between 10 and -1
oksano4ka [1.4K]

Answer:

11

Step-by-step explanation:

To get to 0 from 10 you go 10, then you go one more to -1, for a total of 11

5 0
3 years ago
Read 2 more answers
Solve 91 - 2 + 7k| +1 = 46
mylen [45]

Answer:

k = -6.29

Step-by-step explanation:

91 - 2 + 7k + 1 = 46

add all like terms

90 + 7k =46

subtract

90 + 7k = 46

-90          -90

------------------------

7k = -44

divide

\frac{7k}{7} = \frac{-44}{7} (these arent fractions thats just how i divide things :))

= -6.28571428571

round to nearest hundredth

k= -6.29

goes up to 9 because 5 makes 8 go up one when rounding

sorry for asking so many questions. hope this helps

7 0
3 years ago
Help me with the problem plz 6p6
satela [25.4K]

i need more information to answer the question

5 0
3 years ago
segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc
Elan Coil [88]

Answer:

The magnetic field is B = 3.87 *10^{-6} \ T

Direction is inward

 

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

      The radius of  BC is  r_{BC} =  30 \ cm  =  0.30 \ m

      The radius of  DA is r _{DA} =  20 \ cm =  0.20 \ m

      The length of CD is  r_{CD} =  10 cm =  0.1 \ m

      The length of AB is  r_{AB} =  10 cm =  0.1 \ m

      The current is  I  =  11.4A

The magnetic field is mathematically represented as

      B =  B_{BC} +  B_{DA} + B_{CD} + B_{AB}

       B =  \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]

        Where

                 \theta_{BC} = \theta_{DA} =  \frac{2\pi}{3}

Where  \frac{2 \pi}{3}  =  120^o

                \theta_{CD} = \theta_{AB}  =  0^o

so

        B =  \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]

         B = 3.87 *10^{-6} \ T

The direction is into the page

    This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule  the direction of current is perpendicular to the direction of magnetic field so since  current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0
3 years ago
Y=1/2x+2 need answers on graph
Aneli [31]

Answer:

the slope is 1/2 and the Y - intercept is 2

X       Y

0       2

2       3

Step-by-step explanation:

5 0
3 years ago
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