X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
-8
Step-by-step explanation:
both 8^-8 and 16^-8+2 equal 5.9605
A <span>separable differential equation</span> is a first-order differential equation in which the expression for dy/dx can be factored as a function of x times a function of y,
that is, dy/dx = g(x) f(y). We can solve this equation by integrating both sides of the equation dy/f(y) = g(x)dx.
39x-3y=21
-3y=21-39x
(subtract both sides of the equation by 39x and divide both sides by -3)
y=-7+3x : would be the equation for y.
If the denominator of this fraction was 80, the numerator would have to be 44
