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2 years ago

Use FOIL to multiply. (3x - 7)(x + 5)

Mathematics

2 answers:

Mnenie [13.5K]2 years ago

4 0

3x^2-7x+15x-35
=3x^2+8x-35

Natalija [7]2 years ago

4 0

Answer:

3x²+8x-35

Step-by-step explanation:

FOIL stands for:

First -> (3x-7)(x+5)

Outer -> (3x-7)(x+5)

Inner -> (3x-7)(x+5)

Last -> (3x-7)(x+5)

Following FOIL, we get:

(3x-7)(x+5)

(3x)(x)+(3x)(5)+(-7)(x)+(-7)(5)

3x²+15x-7x-35

3x²+8x-35

Therefore, the expanded form is 3x²+8x-35

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ANSWER

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EXPLANATION

The given expression is

$(9 {c}^{ - 9} )^{ - 3}$

Recall that:

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We use the law of exponents to get

$(9 {c}^{ - 9} )^{ - 3} = 9^{ - 3} {c}^{ - 9 \times - 3}$

Let us multiply in the exponents to get:

$(9 {c}^{ - 9} )^{ - 3} = 9^{ - 3} {c}^{ 27}$

Recall again that:

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This implies that:

$(9 {c}^{ - 9} )^{ - 3} = \frac{1}{ {9}^{ 3} } \times {c}^{ 27}$

We expand the power to get:

$(9 {c}^{ - 9} )^{ - 3} = \frac{1}{9 \times 9 \times 9} \times {c}^{ 27}$

$(9 {c}^{ - 9} )^{ - 3}=\frac{1}{729} \times {c}^{ 27}$

We multiply out to get:

$(9 {c}^{ - 9} )^{ - 3}=\frac{{c}^{ 27} }{729}$

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