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Mariana [72]
2 years ago
10

Cuántos años tendre en 2030 si tengo 16 en 2022?​​

Mathematics
1 answer:
stepan [7]2 years ago
8 0

¿Cuántos años tendre en 2030 si tengo 16 en 2022?

Resolvamos:

\:  \: {\sf \rightarrow2030 - 2022 = 82030−2022=8}

\:  \:  \sf \rightarrow16 + 8 = 2416+8=24

Entonces, Tendrás 24 años en 2030.

Espero que te sirva, salu2!!!!

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√₂
snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

brainly.com/question/28350785

5 0
1 year ago
Solve for X<br><br> PLEASE HELP ME
guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180°             Supplementary Angles

Step 2:

x° + 170° = 180°         Combine Like Terms

Step 3:

x° = 180° - 170°       Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0
3 years ago
Which word is used to name the bold number?
EastWind [94]
A <<<<<<<{<<<<<<<<<<<
5 0
3 years ago
Clark has 7 and a half feet of wire. Part A: How many 3 over 4 foot pieces can Clark cut from the 7 and a half feet of wire? Sho
DIA [1.3K]
A) 7.5/3=2.5 

b) So about 3 pieces can be cut.
3 0
3 years ago
z varies jointly with x and y. When x = 2 and y = 3, z = 60. What is the value of z when x = 4 and y = 9?
kondor19780726 [428]
2 x 3 = 6 x 10 = 60
<em>Assuming that you are using the same rule:
</em><em>4 x 9 x 10 = 360
</em>The value of z when x = 4 and y = 9 is 360. Hope this helped!
6 0
3 years ago
Read 2 more answers
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