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3 years ago

10

Cuántos años tendre en 2030 si tengo 16 en 2022?

1 answer:

stepan [7]3 years ago

8 0

¿Cuántos años tendre en 2030 si tengo 16 en 2022?

Resolvamos:

$\: \: {\sf \rightarrow2030 - 2022 = 82030−2022=8}$

$\: \: \sf \rightarrow16 + 8 = 2416+8=24$

Entonces, Tendrás 24 años en 2030.

Espero que te sirva, salu2!!!!

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3 years ago

Roberta has $10,540 to invest. She plans to invest her money in certificates of deposit (CDs) that have 2.1% interest, a stock p

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Answer:

The amount invested in CDs is $1,340

The amount invested in the stock portafolio is $6,900

The amount invested in the saving accounts is $2,300

Step-by-step explanation:

Let

x ---->the amount invested in CDs at 2.1%

y ---> the amount invested in the stock portfolio at 2.5%

z ---> the amount invested in the savings account at 1.5%

$x+y+z=10,540$ ----> equation A

$z=\frac{1}{3}y$ ----> equation B

substitute equation B in equation A

$x+y+\frac{1}{3}y=10,540$

$x+\frac{4}{3}y=10,540$

$x=10,540-\frac{4}{3}y$ ----> equation C

we know that

The total interest earned by the three amount must be equal to $231.69

so

$0.021x+0.025y+0.015z=231.69$ ----> equation D

substitute equation B and equation C in equation D

$0.021(10,540-\frac{4}{3}y)+0.025y+0.015(\frac{1}{3}y)=231.69$

solve for y

$221.34-0.0315y+0.025y+0.005y=231.69$

$0.0015y=231.69-221.34$

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<em>Find the value of x</em>

$x=10,540-\frac{4}{3}(6,900)$

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<em>Find the value of z</em>

$z=\frac{1}{3}(6,900)$

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4 years ago

Wally is rebuilding his fence. Each section of the fence will have 12 vertical boards that are each eight inches wide. He’s goin

Leokris [45]

Answer:

Part A)

Each diagonal is about 9.43 feet.

Part B)

In total, Wally needs about 736.02 feet of wood.

Step-by-step explanation:

Part A)

Since each vertical board has a width of 8 inches, for one section with 12 vertical boards, the total width will be 8(12) = 96 inches.

96 inches is the same as 96/12 = 8 feet.

We are also given that the horizontal pieces will be 5 feet apart.

To find the diagonal, we can use the Pythagorean Theorem. The 8 is the base and 5 is the height. Therefore:

$\displaystyle d^2=8^2+5^2$

Compute:

$d^2=89$

Taking the square root, we acquire:

$\displaystyle d=\sqrt{89}\approx9.43 \text{ feet}$

So, each diagonal is about 9.43 feet.

Part B)

For each section, we have two horizontal pieces (each 8 feet) and one diagonal piece (each √89 feet).

Therefore, for one section, we will need a total of:

$\displaystyle L=8+8+\sqrt{89}=16+\sqrt{89}$

Then for 30 sections, we will need:

$T=30(16+\sqrt{89})$

Approximate:

$T\approx 763. 02$

Wally will need about 736.02 feet of wood in total.

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3 years ago