Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at a rate of 65
1 answer:
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Answer:
<h2> RS = 47</h2>Step-by-step explanation:
RV=VU and SW=WT ⇒
Therefore:
3x + 5 = 4x - 11 {subtract 5 from both sides)
3x = 4x - 16 {subtract 4x from both sides)
-x = -16 {divide both sides by (-1)}
x=16
So:
RS = 2x + 15 = 2×16 + 15 = 32 + 15 = 47
Answer:
3.9 miles
Step-by-step explanation:
Use phytagoras theorem
c²=a²+b²
4²=1²+b²
16=1+b²
b²=16-1
b²=15
b=
b= 3.872
≈3.9miles
It is given that there are 4 cards with numbers 2, 5, 6, and 8.
1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.
To do this, find the sample space of the draw which are:
Hence, the required numbers.
2) Recall that probability is the ratio:
From the numbers listed, notice that the total number of possible outcomes is 12.
Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).
Hence, the number of favorable outcomes is 9.
Substituting into the probability ratio gives the required probability:
Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).
Hence, the required probability of event B is:
The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.
Hence, the required probability of event C is:
Answers:
1) {25,26,28,52,56,58,62,65,68,82,85,86}
2) P(A) = 3/4
P(B) = 1/4
P(C)= 0