what is an equation of the line that passes through the point (-8,0) and is parallel to the line x+2y=14

1 answer:

6 0

Answer:

y = -1/2x - 4

Step-by-step explanation:

First we wanna convert x + 2y = 14 into a slope-intercept equation.

x + 2y = 14

2y = 14 - x

y = 7 - x/2 or y = -1/2x + 7

Now that we have the line in slope-intercept form, we can solve for a line that is parallel to.

But first, what do parallel lines have in common? Parallel lines never intersect first of all and second they have the same slope so meaning we’re going to use -1/2 in order to find the equation of a parallel line so…

y = -1/2x + b

use the given point in the question

0 = -1/2(-8) + b

0 = 4 + b

b = 0 - 4

b = -4

The y-intercept of the line is -4

The equation of the line that passes through the point (-8, 0) and is parallel to the line x + 2y = 14 is y = -1/2x - 4

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So, first lets define our variables:

let x = the number of dimes
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so our first equation would be x+y = 16

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.10x+.05y = 1.35

now change the first equation so y = -x+16
now substitute:

.10x+.05(-x+16) = 1.35
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