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Marianna [84]
2 years ago
11

what is an equation of the line that passes through the point (-8,0) and is parallel to the line x+2y=14

Mathematics
1 answer:
dmitriy555 [2]2 years ago
6 0
Answer:

y = -1/2x - 4

Step-by-step explanation:

First we wanna convert x + 2y = 14 into a slope-intercept equation.

x + 2y = 14

2y = 14 - x

y = 7 - x/2 or y = -1/2x + 7

Now that we have the line in slope-intercept form, we can solve for a line that is parallel to.

But first, what do parallel lines have in common? Parallel lines never intersect first of all and second they have the same slope so meaning we’re going to use -1/2 in order to find the equation of a parallel line so…

y = -1/2x + b

use the given point in the question

0 = -1/2(-8) + b

0 = 4 + b

b = 0 - 4

b = -4

The y-intercept of the line is -4

The equation of the line that passes through the point (-8, 0) and is parallel to the line x + 2y = 14 is y = -1/2x - 4
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Answer:

Step-by-step explanation:

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Substituting x in (1) in (2)

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3 years ago
Can someone help me figure this out no guessing
laiz [17]
Your answer is x = 2.92 = 3.
To answer this question you need to use trigonometry, so the first step is to identify the hypotenuse, opposite, and adjacent.
Because the angle 73 is in the bottom corner next to the length x, we know that the length x is the adjacent. The length 10 is opposite the right angle so this must be the hypotenuse.
We know that cos(θ) = adjacent/hypotenuse, so we can substitute in what we know:
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cos(73) = x/10
Now we can rearrange for x:
cos(73) = x/10
× 10
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Finally we just type this into the calculator and get the answer as 2.92 or 3.
I hope this helps!
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Step-by-step explanation:

I don't know what the q value of this is, but I found the vertex for you.

I hope that this helps!

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