Answer:
C. y +3 = x +3
Step-by-step explanation:
We need to find in below option x has direct variation with y.
We solve for each;
A. ![2y = 3x-7](https://tex.z-dn.net/?f=2y%20%3D%203x-7)
From above equation we can state that 2 times y is equal to 7 less than 3 times of x.
Hence it doesn't represent direct variation.
B. ![y-4 = x+6](https://tex.z-dn.net/?f=y-4%20%3D%20x%2B6)
Solving above expression we get;
![y-4 = x+6\\y = x+6+4\\y=x+10](https://tex.z-dn.net/?f=y-4%20%3D%20x%2B6%5C%5Cy%20%3D%20x%2B6%2B4%5C%5Cy%3Dx%2B10)
From above equation we can state that y is equal to 10 more than x.
Hence it doesn't represent direct variation.
C. ![y+3 = x+3](https://tex.z-dn.net/?f=y%2B3%20%3D%20x%2B3)
Solving above expression we get;
![y+3 = x+3\\y = x+3-3\\y=x](https://tex.z-dn.net/?f=y%2B3%20%3D%20x%2B3%5C%5Cy%20%3D%20x%2B3-3%5C%5Cy%3Dx)
From above equation we can state that y is equal to x.
Hence it represent direct variation.
D. ![4y+1 = 4x-1](https://tex.z-dn.net/?f=4y%2B1%20%3D%204x-1)
Solving above expression we get;
![4y+1 = 4x-1\\4y = 4x-1-1\\4y=4x-2](https://tex.z-dn.net/?f=4y%2B1%20%3D%204x-1%5C%5C4y%20%3D%204x-1-1%5C%5C4y%3D4x-2)
From above equation we can state that 4 times y is equal to 2 less than 4 times of x.
Hence it doesn't represent direct variation.
Hence the Answer which represent direct variation of x and y is,
C. ![y+3 = x+3](https://tex.z-dn.net/?f=y%2B3%20%3D%20x%2B3)
Answer:An absolute value inequality is solved by re-writing it as compound inequality. For example.
|x+1| < 5
Since the value inside the absolute value brackets: (x+1) can be positive or negative, it is re-written as a compound inequality as the example below.
x+1 < 5
x+1 > - 5
solve for the range of values x can be
-6 < x < 4
Step-by-step explanation: How to solve inequalities
6x^2 - 8 = 4x^2 + 7x
6x^2 - 4x^2 - 7x - 8 = 0
2x^2 - 7x - 8 = 0
discriminant = b^2 - 4ac; where a = 2, b = -7 and c = -8
d = (-7)^2 - 4(2)(-8)
d = 49 + 64
d = 113
the discriminant is greater than zero, so there are two real roots
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers.