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Scrat [10]
2 years ago
14

Answer the Question the volume based Question. I will make uh brainliest + 50 points​

Mathematics
1 answer:
Dimas [21]2 years ago
4 0
<h3><u>Part A</u></h3>

To show the total capacity of container B is 132 cm³

volume = unit rate × time taken

volume = 6 cm³ × 22

volume = 132 cm³ ∴ Hence proved.

<h3 /><h3><u>Find radius</u></h3>

\sf volume \ of \ cone = \dfrac{1}{3} \pi r^2 h

===================

\rightarrow \sf \dfrac{1}{3} * \dfrac{22}{7}  * r^2 * 14 = 132

<em>simplify</em>

\rightarrow \sf  \dfrac{44}{3}  * r^2= 132

<em>change sides</em>

\rightarrow \sf r^2= \dfrac{132(3)}{44} = 9

<em>square root both sides</em>

\rightarrow \sf r = 3

∴ Hence the radius of cone (Shape B is 3 cm)

<h3><u>To show the time taken</u></h3>

volume = unit rate × time taken

\sf volume  \ of \ hemi -sphere = \dfrac{2}{3} \pi r^3

=========================

\sf \rightarrow  \dfrac{2}{3} \pi r^3 = 6 * time  \ taken

<em>Insert values</em>

\sf \rightarrow  \dfrac{2}{3} *\dfrac{22}{7}  \  r^3 = 6 * time  \ taken

<em>exchange sides</em>

\sf \rightarrow   time  \ taken =  \dfrac{2}{3} *\dfrac{22}{7}  \  r^3 *\dfrac{1}{6}

<em>simplify following</em>

\sf \rightarrow   time  \ taken =  \dfrac{22}{63}r^3

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AB=\sqrt{53},\ BC=\sqrt{40},\ CA=\sqrt{41}\\It\ is\ an\ acute\ triangle

Step-by-step explanation:

The distance between two points (x_1,y_1),\ (x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Here A(1,5),\ B(3,-2),\ C(-3,0) are the vertices of a triangle.

AB=\sqrt{(-2-5)^2+(3-1)^2}=\sqrt{(-7)^2+(2)^2}=\sqrt{49+4}=\sqrt{53}=7.28\ unit\\\\BC=\sqrt{(0+2)^2+(-3-3)^2}=\sqrt{(2)^2+(-6)^2}=\sqrt{4+36}=\sqrt{40}=6.32\ unit\\\\CA=\sqrt{(5-0)^2+(1+3)^2}=\sqrt{(5)^2+(4)^2}=\sqrt{25+16}=\sqrt{41}=6.40\ unit

Longest side=AB

AB^2=53\\BC^2+CA^2=40+41=81\\\Rightarrow AB^2

Hence this is an acute triangle.

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