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KIM [24]
3 years ago
14

Lannister checks out 6 set of books from the library each set has the same number of books she reads 7 of the books and she has

11 books left to read how many books are in each sets
Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

3

Step-by-step explanation:

Lannister checks out 6 sets of book

Each set had the same number of books

She reads 7 books and has 11 more to go

Therefore the number of books in each set can be calculated as follows

= 11+7

= 18

18/6

= 3

Hence there are 3 books in each set

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5 0
3 years ago
Pleaseee i need some help on these 3 questions
Zepler [3.9K]

Answer:

a) the product is equal to 953.

b) the product is greater than 443.

c) the product is greater than 181.

Step-by-step explanation:

a) 953 × 63/63 = 953

Therefore, the product is equal to 953.

b) 443 × 86/79 = 482.25

Therefore, the product is greater than 443.

c) 181 × 30/28 = 193.93

Therefore, the product is greater than 181.

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6 0
2 years ago
The graph of a quadratic function having the form f(x) = ax? + bx + c passes
insens350 [35]

Answer:

  f(-3) = -20

Step-by-step explanation:

We observe that the given x-values are 3 units apart, and that the x-value we're concerned with is also 3 units from the first of those given. So, a simple way to work this is to consider the sequence for x = 6, 3, 0, -3. The corresponding sequence of f(x) values is ...

  34, 10, -8, ?

The first differences of these numbers are ...

  10 -34 = -24

  -8 -10 = -18

And the second difference is ...

  -18 -(-24) = 6

For a quadratic function, second differences are constant. This means the next first-difference will be ...

  ? -(-8) = -18 +6

  ? = -12 -8 = -20

The value of the function at x=-3 is -20.

_____

The attachment shows using a graphing calculator to do a quadratic regression on the given points. The graph can then be used to find the point of interest. There are algebraic ways to do this, too, but they are somewhat more complicated than the 5 addition/subtraction operations we needed to find the solution. (Had the required x-value been different, we might have chosen a different approach.)

5 0
3 years ago
Please help me with some Algebra 2. Last stretch of the trimester and it’s 3:13AM. It’s my own fault for getting myself into thi
son4ous [18]

Answer:

A. 23+(6-1)x-3

B. 93

Step-by-step explanation:

a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

            = 23 + (5) x -3

            = 23 + (-15)

            = 8 - number of boxes in the top row.

b) Sum = N/2[2F + (N - 1) x D]

            = 6/2[2*23 + (6 - 1) x -3]

             = 3  [46  +    (5) x -3 ]

             = 3  [46  +      -15 ]

             = 3  [ 31 ]

             = 93 - total number of boxes in the entire display.

Hope this helps! Its 3:25 AM for me too so I know how you feel.

5 0
3 years ago
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