The standard equation of a circle is:
where (h,k) is the center and r is the radius.
We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.
The bolded part is your answer. Since the radius is not given, we can put any value.
9514 1404 393
Answer:
64/109 ≈ 0.5872
Step-by-step explanation:
41 + 23 = 64 of the events have outcome E.
An additional 35 + 10 = 45 do not.
The probability of an outcome of E is 64 out of a total of 64+45 = 109 events.
P(E) = 64/109 ≈ 0.5872
Answer:
At least 202.44 mm in the top 15%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
How many yearly mm of rainfall would there be in the top 15%?
At least X mm.
X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.
At least 202.44 mm in the top 15%.
D=2r so the diameter is 10.4ft. Multiple 10.4ft by 3.14 to get the answer. The answer is 32.656
