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Mice21 [21]
2 years ago
11

What's the square root of Pi times the c length of a right triangle with the a measurement of 12 and the b measurement of 10?

Mathematics
1 answer:
allochka39001 [22]2 years ago
4 0

Answer:

2\sqrt{61\pi }

Step-by-step explanation:

Let's find c by using the Pythagorean Theorem: 10^2 + 12^2 = c^2 so c = \sqrt{10^2 + 12^2}. I'm going to leave c like this so it is easier to multiply by \sqrt{\pi }. c\sqrt{\pi }  = \sqrt{10^2 + 12^2}\sqrt{\pi } = 2\sqrt{61\pi }.

Hope this helped! :)

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How do you solve for M in the formula?<br>Give Steps Please!​
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Answer:

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4 0
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Read 2 more answers
If a and b are the measures of two first quadrant angles and sin a = 4/9 and sin b = 2/5 find sin(a+b).
frutty [35]

Answer:

sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}

Step-by-step explanation:

we are given

sin(a)=\frac{4}{9}

sin(b)=\frac{2}{5}

Firstly, we will draw triangle

we get

cos(a)=\frac{\sqrt{65} }{9}

cos(b)=\frac{\sqrt{21} }{5}

now, we can sue formula

sin(a+b)=sin(a)cos(b)+cos(a)sin(b)

now, we can plug values

sin(a+b)=\frac{4}{9}\times \frac{\sqrt{21} }{5}+\frac{\sqrt{65} }{9}\times \frac{2}{5}

now, we can simplify it

sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}


6 0
3 years ago
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