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pashok25 [27]
3 years ago
10

state the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

  • domain (-∞, ∞)
  • range (-∞, 4]
  • increasing (-∞, 0)
  • decreasing (0, ∞)
  • constant (only at x=0, not on any interval)

Step-by-step explanation:

The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).

The vertical extent of the graph includes y=4 and all numbers less than that:

  range: (-∞, 4]

The graph is increasing to the left of its vertex at x=0, decreasing to the right.

  increasing (-∞, 0); decreasing (0, ∞)

There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.

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1. Find domain of the function, = ln(2 − 6 − 55).
Bingel [31]
Domain of a function

We want to find the domain of the following function:

=ln\mleft(^2-6-55\mright)

This means that we want to find the x-values that it can take.

<h2>STEP 1: analyzing the simplies form of the function</h2>

Let's analyze the simpliest form of the function:

=ln(x)

Its graph is:

Then, for the simpliest form of the function, the x-values can only be higher than 0.

This means that its domain is

domain = x > 0

<h2>STEP 2: domain of the given function</h2>

Based on the above we can deduce that for the <em>ln(x)</em> function, what is inside the parenthesis should be higher than 0 on this kind of functions.

This is that for

=ln\mleft(^2-6-55\mright)

then

^2-6-55>0<h2>STEP 3: finding the x values that make x²-6x-55>0 (factoring)</h2>

In order to find the values of x that make

^2-6-55>0

we must factor it.

We want to find a pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6).

For the last term of the polynomial: -55, we have that

(-5) · 11 = 55

5 · (-11) = 11

If we add them:

-5 + 11 = 6

5 - 11 = -6

The pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6), are: 5 and -11

We use them to factor the polynomial:

^2-6-55=(x+5)(x-11)

Then,

(x+5)(x-11)>0<h2>STEP 4: finding the x values that make (x+5)(x-11)>0 (factoring)</h2>

In order to find them, we are going to separate the factors (x+5) and (x-11) and analyze when they are positive or negative:

Combining them:

Since we are going to multiply both factors:

(x+5)(x-11)

We use the diagram to analyze the sign of their product:

Then

(x+5)(x-11)>0

when x < -5 and when x > 11. This is the domain.

Therefore, expressed in set notation:

domain = {x|x∈(-∞, -5)∪(11, ∞)}

<h2>Answer: domain = {x | x ∈ (-∞, -5)∪(11, ∞)}</h2>

5 0
1 year ago
The random variable X is exponentially distributed, where X represents the time it takes for a person to choose a birthday gift.
NeX [460]

Answer:

0.674

Step-by-step explanation:

If the random variable X is exponentially distributed and X has an average value of 25 minutes, then its probability density function (PDF) is

\bf f(x)=\frac{1}{25}e^{-x/25}\;(x\geq 0)

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So, <em>the probability that X is less than 28 minutes is </em>

\bf P(X\leq 28)=1-e^{-28/25}=1-e^{-1.12}=0.674

8 0
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