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2 years ago

Calculate the area of the following composite figure.

Mathematics

2 answers:

Alexeev081 [22]2 years ago

4 0

$\bold{ANSWER:}$
100 units^2

$\bold{EXPLANATIONS:}$

Lubov Fominskaja [6]2 years ago

3 0

You could actually convert the shape into a rectangle. By moving the two triangles at the bottom, to fit in the top. Then, the length times width
10x5=50
The answer is 50

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Solve the equations. a. (x − 2)^2 = 9 b. 3(x − 2)^2 = 9 c. 6 = 24(x + 1)^2

seropon [69]

Answer: a) x = 5 or -1 b) x = √3+2

c) x = -1/2 or -3/2

Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

x-2 = +-3

x = +3+2

x = 5 and;

x = -3+2

x = -1

x = 5 or -1

b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

√(x-2)² = √3

x-2 = √3

x = √3+2

c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

x = -1/2 or -3/2

4 0

3 years ago

What is the value of x? Enter your answer in the box.

12345 [234]

2x - 4 = 60
2x = 64
x = 32

hope it helps

5 0

3 years ago

The overnight temperature in Tampa never reach below 40°F during november. wich inquality shows that

notsponge [240]

x≥40 is the answer to your problem

7 0

3 years ago

What is the focus of the parabola given the equation y=x^2+4x-1

IrinaK [193]

Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5

Now, 4a = 1; a = $\frac{1}{4}$

So, the vertex form is (x + 2)² = 4( $\frac{1}{4}$ )(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.

∴ F(-2, -5 + $\frac{1}{4}$ )
F(-2, $\frac{-19}{4}$ )

3 0

2 years ago

Louis built a swimming pool. The depth of the swimming pool is 5 feet. What is the volume of water that it will take to fill the

julia-pushkina [17]

Answer:

For a rectangular prism-like swimming pool: $V = w\cdot l \cdot h$ . $V = 360\,ft^{3}$ when $h = 5\,ft$ , $l = 12\,ft$ and $w = 6\,ft$ .

Step-by-step explanation:

Let assume that swimming pool has a rectangular base and depth is the same at any point at the bottom. In addition, let $w$ and $l$ be the width and length of the swimming pool. Then, the volume needed to fill the swimming pool is:

$V = w\cdot l \cdot h$ , where $h$ is the depth of the pool.

Let be $h = 5\,ft$ , $l = 12\,ft$ and $w = 6\,ft$ . The volume of the swimming pool is:

$V = (6\,ft)\cdot (12\,ft)\cdot (5\,ft)$

$V = 360\,ft^{3}$

3 0

3 years ago