Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = ![\frac{1}{2}(\text{AD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BAD%7D%29)
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= ![\frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BTotal%20number%20of%20segments%20measuring%20greater%20than%203%7D%7D%7BTotal%20number%20of%20segments%7D)
= ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
= 0.6
The dimensions of the rectangular cross section will be<u> 10 centimeters by 18 centimeters</u>
<u></u>
Step-by-step explanation:
As ,we know
<u>The rectangular cross section is parallel to the front face</u>
Which clearly states that
The dimensions of the rectangular cross section is congruent with the dimensions of the front face
Lets assume that dimensions of the front face are 10 centimeters by 18 centimeters
<u>Then ,The dimensions of the cross section will also be 10 centimeters by 18 centimeters</u>
<u></u>
<u>Hence we can say that the</u> dimensions of the rectangular cross section will be<u> 10 centimeters by 18 centimeters</u>
How to:
a+b-mx=0
a+b=mx
(a+b)/x=m
Answer:
<em>$195</em>
Step-by-step explanation:
15a + 12c
5 adults and 10 children means a = 5 and c = 10
15a + 12c = 15(5) + 12(10) = 75 + 120 = 195
This may help you but I'm not so sure tho