The hanger image below represents a balanced equation.
1 answer:
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Given that t<span>here
are 20 light bulbs in 5 packages.
The table to find the rate that gives you the number of light bulbs in 3 packages is given as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Light bulbs&4&8&12&16&20\\[1ex] Packages&1&2&3&4&5 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ALight%20bulbs%264%268%2612%2616%2620%5C%5C%5B1ex%5D%0APackages%261%262%263%264%265%0A%5Cend%7Btabular%7D)
Three different ways in which the rate can be written are:
12 light bulbs to 3 packages
12 light bulbs : 3 packages
12 light bulbs / 3 packages
</span>
The table to find the rate that gives you the number of light bulbs in 3 packages is given as follows:
Three different ways in which the rate can be written are:
12 light bulbs to 3 packages
12 light bulbs : 3 packages
12 light bulbs / 3 packages
</span>
Answer:
the answer is 3
Step-by-step explanation:
First change the whole number (3) to quaters or fraction
3x =
Now, add
+
=
Since, we have the same common denominator
now divide
14÷4 =3.5 = 3
Therefore, there are 3 of 3/4 with a remainder of in 3
.