Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
So perimeter is equal to 2 lengths and 2 width so the equation would be P=2L+2W. you know width so you plug in 5 for W then solve for L and you should get L=3
Answer:
x = ± 
Step-by-step explanation:
Given
y = x² + 11 ( subtract 11 from both sides )
y - 11 = x² ( take the square root of both sides )
± = 
, hence
x = ±
Answer:
Number of sand bags needed = 124
Step-by-step explanation:
Diameter of garden = 40 yd
Width of path = 6 yd
Diameter of garden with path = 40 + 2 x 6 = 52 yd
We need to find area of path.
Area of path = Area of garden with path - area of garden
Area covered by one sand bag = 7 yd²
Number of sand bags needed = 124
