A(b+c)=ab+ac
we have
9(72)=9*?+9*2
c=2
sub, but it must be equal to minus 2 from 72
7(70+2)=9*70+9*2
the question mark is 70
and the restult of the equation is 648
?=70
We have
AP = 34,36,38......,234
a, (first term) = 34
n ( total terms ) =?
d ( common difference ) = 2
so, a +(n-1)d =an
34+(n-1)*2 = 234
(n-1)2 = 234-34
n-1 = 200/2
n = 100+1
n =101
Now sum of the even no.
Sn = n/2( 2a+9n-1)d)
= 101/2 (2*34 +100*2)
= 101/2 * 268
=101 *134
= 13534
Answer:
x=1
Step-by-step explanation:
First, we must simplify it to standard form:
Step-by-step explanation:
Rule: The sum of any integer and its opposite is equal to zero. Summary: Adding two positive integers always yields a positive sum; adding two negative integers always yields a negative sum. To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values.
Answer:
16-(4*x)-(4*x^2)+x^3
Step-by-step explanation:
(x+2)(x-2)(x-4)
16-(4*x)-(4*x^2)+x^3
