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andrew11 [14]
3 years ago
9

The sand pit has a width of 2.56meters and a length of 8.75meters. Just in case it rains, the principal wants to cover the sand

pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

The answer is below

Step-by-step explanation:

The piece of plastic needed to cover the sand pit is the same as the area of the sand pit. Since the sand pit has a width of 2.56meters and a length of 8.75meters, it means that the sand pit is rectangular in shape. The area of the sand pit is given by the formula:

Area = length × width

Area = 2.56 meters × 8.75 meters

Area = 22.4 m²

The plastic needed to cover the sand pit needs to have an area of 22.4 m²

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Answer:

Bobby around 131 minutes and Billy around 111 minutes

Step-by-step explanation:

To solve the problem it is important to raise equations regarding what happens.

 They tell us that Billy (Bi) and Bobby (Bo) can mow the lawn in 60 minutes. That is to say that what they prune in a minute is giving as follows:

1 / Bo + 1 / Bi = 1/60 (1)

They say Billy could mow the lawn only in 20 minutes less than it would take Bobby, therefore

1 / Bi = 1 / (Bo-20) (2)

Replacing (2) in (1) we have:

1 / Bo + 1 / (Bo-20) = 1/60

Resolving

(Bo - 20 + B0) / (Bo * (Bo-20) = 1/60

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Rearranging:

Bo ^ 2 - 140Bo -1200 = 0

Now applying the general equation

Bo = 130.82 or Bo = 9.17, <em>this last value cannot be because Billy took 20 minutes less and neither can he prune faster than the two together</em>, therefore Bobby only takes around 131 minutes and Billy around 111 minutes

Checking with equation 1:

1/131 +1/111 = ~ 1/60

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