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andrew11 [14]
3 years ago
9

The sand pit has a width of 2.56meters and a length of 8.75meters. Just in case it rains, the principal wants to cover the sand

pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

The answer is below

Step-by-step explanation:

The piece of plastic needed to cover the sand pit is the same as the area of the sand pit. Since the sand pit has a width of 2.56meters and a length of 8.75meters, it means that the sand pit is rectangular in shape. The area of the sand pit is given by the formula:

Area = length × width

Area = 2.56 meters × 8.75 meters

Area = 22.4 m²

The plastic needed to cover the sand pit needs to have an area of 22.4 m²

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(1 point) A chain 64 meters long whose mass is 24 kilograms is hanging over the edge of a tall building and does not touch the g
miss Akunina [59]

Answer:

W = 2747,1 [J]

Step-by-step explanation:

Chain is 64 meters long with mass 24 Kg

Then weight of the chain is p = 24 * 9.8

p = 235.2 [N]         N = kg*m/s²

And by meter is 235,2 / 64    = 3.675

Total work has two component

- work to lift the 13 top meters of chain  W₁

W₁ = ∫₀ᵇ F(y) dy

- work to lift last ( 64 - 13 ) meters  51   W₂

W₂ = 3.675 * 51 * 13      Kg m² /s²   [J]

W₂ =  2436,53 [J]

We need to calculate  W₁

W₁  = ∫¹³₀ mgy dy    ⇒     W₁  = ∫¹³₀ 3,675 ydy

W₁  = 3,675* ∫¹³₀ ydy     W₁  = 3,675* y²/2  |₀¹³

W₁  = 3,675* 84,5 [J]

W₁  = 310,54 [J]

And total work W

W = W₁ + W₂

W = 310,54  + 2436,53 [J]

W = 2747,1 [J]

8 0
3 years ago
The bakery is selling bagels at a cost of 6 for $7.50. at that rate, how much would 8 bagels cost?
alexira [117]
6:7.50=8:x
6x=7.50*8=60
x=10.00
7 0
3 years ago
Change 3/2 to a mixed number
Mariulka [41]
Okay first you have to divide 
2 goes into 3
3/2
2 fits into 3 once
1 and the left over is 1 so
1 1/2

4 0
3 years ago
An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou
Katyanochek1 [597]

Answer:

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

p_v =P(t_{(5)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation  

The mean and sample deviation can be calculated from the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}

\bar X=29.35 represent the sample mean  

s=1.365 represent the sample standard deviation  

n=6 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :  

Null hypothesis:\mu \geq 30  

Alternative hypothesis:\mu < 30  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=6-1=5  

Since is a one-side left tailed test the p value would given by:  

p_v =P(t_{(5)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

5 0
2 years ago
For what value of q is in the question -13(q+4)=7q+16​
Rufina [12.5K]

Answer:

q=-3 2/5

Step-by-step explanation:

First multiply -13 with (q+4)

-13q-52=7q+16

Now you have to change the order before = the numbers with q and after = the numbers without anything

-13q-7q=52+16

Remember that when you change positions the symbol too

Then solve it

-20q=68

Now u have to divide as i do

q=68/-20

you can simplify it

q=3 8/-20

Now divide by the greater divisor in this case is 4

q=3 2/-5

And organize it

q=-3 2/5

Never forget to do q=(answer)

Hopefully it helps.

5 0
3 years ago
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