A student mixes 40. Ml of 0. 10mhbr(aq) with 60. Ml of 0. 10mkoh(aq) at 25°c. What is the [oh−] of the resulting solution?
1 answer:
After the complete neutralization reaction occurs, excess hydroxide ion is left unreacted the hydroxide ion of the resulting solution, [OH-] is 0.02 M.
<h3>What is the concentration of the hydroxide ion, [OH-]?</h3>The hydroxide ion concentration is the amount in moles of hydroxide ion in a solution.
The hydroxide ion concentration is written as [OH-].
The equation of the reaction is given below:
1 mole of HBr reacts with 1 mole of KOH
Moles of HBr = 40 mL × 0.1 M = 4 mm moles
Moles of KOH = 60 mL × 0.1 M = 6 m moles
Moles of [OH-] = 6 - 4 = 2 m moles
Volume of solution = 100 mL
Thus, the concentration of the hydroxide ion, [OH-] is 0.02 M.
Learn more about hydroxide ion
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<h2>Hello!</h2>
The answer is:
We have that there were produced 0.120 moles of
We are asked to calculate the number of moles of the given gas, also, we are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.
The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:
Where,
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles of the gas.
T is the absolute temperature of the gas (Kelvin).
R is the ideal gas constant (to work with pressure in mmHg), which is equal to:
We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.
We can convert from Celsius degrees to Kelvin using the following formula:
So, we are given the following information:
Now, isolating the number of moles, and substituting the given information, we have:
Hence, we have that there were produced 0.120 moles of
Have a nice day!