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matrenka [14]
3 years ago
15

If the earth was a guava fruit, the space where the seeds are would be the core/mantle​

Chemistry
2 answers:
Bezzdna [24]3 years ago
8 0
Good analysis lol ...
Andrews [41]3 years ago
4 0
Right on ! I need to answer a question to get mine answered so here I am :)
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Determine the chemical formulas for the two compounds below. (Carbon, Hydrogen, and Oxygen).
tester [92]
Remember that any intersection of lines is a C, and that the number of hydrogens attached are the necessary to complet the 4 bonds.

1) CH3 - CH (OH) - CH (CH3) -CH3

2) CH3 - O - CH(CH3)-CH2 - CH3

I have used the parenthesis to indicate that the radical inside is in other branch, bonded by a single line -
4 0
3 years ago
What is the empirical formula of a compound containing 12 g of carbon, 2 g of hydrogen, and 16 g of oxygen only
Hoochie [10]

Answer:

The empirical formula=CHO. To explain it is C1H1O1 but we don't put the one that's why it is CHO

Explanation:

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3 years ago
What is the average range of the PH scale?<br><br> THANKS!!
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3 years ago
Read 2 more answers
In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account
hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0
3 years ago
Drive down any three characteristic of modern periodic table​
Nitella [24]
Electronegativity
Atomic radius
Ionization energy
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