We have that
<span>If (5x-4+13x=5) --------------> then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>
Variance is the standard deviation squared but we're not going to use that now. Let's first calculate the mean:
mean = (17+13+13+22+11+20)/6 = 16.
Now for each value, let's see how far it is from this mean. We'll square these distances and average them. That's our variance.
17 distance 1 squared = 1
13 distance 3 squared = 9
13 distance 3 squared = 9
22 distance 6 squared = 36
11 distance 5 squared = 25
20 distance 4 squared = 16
Now average these outcomes:
variance = (1+9+9+36+25+16)/6 = 16.
So the variance by coincidence is the same as the mean.
Answer C is your answer.
Answer:
781250
Step-by-step explanation:
Let y is the length of the farm field
Let x is the width of the farm field
Given that, no fencing is necessary along the rock wall, so we can find the perimeter of the farm is:
2x + y = 2500 feet
<=> y = 2500 -2x
The are of the farm has the following formula:
A = x*y
<=> A = x(2500 - 2x)
<=> A = 2500x -2
To have the maximum area of field in square feet, we need to use differentials to estimate:
= 2500 - 4x
Set = 0, we have:
2500 - 4x = 0
<=> x = 625 feet.
=> y = 2500 - 2*625 = 1250 feet
So the maximum area of field is:
A = x*y = 625*1250 = 781250
We know that
the number of coins that each roll contains is
<span>rolls of quarters-------> 40 coins
</span><span>rolls of Dimes---------> 50 coins
</span><span>rolls of nickels------> 40 coins
</span><span>four rolls of quarters------> 4*40*$0.25-----> $40
</span>t<span>hree rolls of Dimes-----> 3*50*$0.10------> $15
</span><span>six rolls of nickels-------> 6*40*$0.05-----> $12
total=[40+15+12]------> $67
the answer is
$67</span>