3 years ago

What is the answer to -3(x-3)

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

Answer:

-3x+9

Step-by-step explanation:

we just need to do the distribution step

-3x-(-3) *(-3)=-3x+9

You might be interested in

brent went for a bycile ride the clocks shows the start time and the end time how long did he ride his bycile the start time is

ozzi

The answer is 40 minutes

6 0

3 years ago

Use an iterated integral to find the area of the region bounded by the graphs of the equations.

Goryan [66]

Answer:

use photomath and it will solve ur problem

5 0

2 years ago

Rewrite the equation y – 4x = –9 in slope-intercept form.

torisob [31]

Answer: y=4x-9

explanation: move the -4x over to the other side and it becomes positive 4x and -9 stays the same.

4 0

3 years ago

Read 2 more answers

I need help with this problem! I'll give brainlist!

aliya0001 [1]

Step-by-step explanation:

use CAH method (Cos angle = adjacent/hypotenuse)

Given adjacent = 5

Hypotenuse = 12,

$\cos(x) = \frac{adjacent}{hypotenuse} \\ \cos(x) = \frac{5}{12} \\ x = {cos}^{ - 1} ( \frac{5}{12} ) \\ = 65.4deg(nearest \: tenth)$

4 0

3 years ago

..................................

yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

$let \: x = a \cos(θ) \\ let \: y = a \sin( θ)$

${x}^{2} + {y}^{2} = {(a \cosθ )}^{2} + {(a \sinθ) }^{2}$

${x}^{2} + {y}^{2} = {a}^{2}( {cos}^{2}θ) + {a}^{2} ({sin}^{2}θ)$

Next, you have to apply Basic Trigonometric Identity :

${sin}^{2} θ + {cos}^{2} θ = 1$

${x}^{2} + {y}^{2} = {a}^{2} ( {cos}^{2} θ + {sin}^{2} θ)$

${x}^{2} + {y}^{2} = {a}^{2} (1)$

${x}^{2} + {y}^{2} = { a}^{2}$

8 0

2 years ago

What is the answer to -3(x-3)​

What is the answer to -3(x-3)