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sweet [91]
2 years ago
5

Find the numerical value of the area under the standard normal curve that is above the mean

Mathematics
1 answer:
sergey [27]2 years ago
4 0

Answer:

  0.5

Step-by-step explanation:

The standard normal curve is symmetrical about the mean, which is also the median and the mode.

That means half the area is above the mean. The whole curve has an area of 1, so ...

  the numerical value of the area above the mean is 0.5

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The perimeter of an isosceles trapezoid is 28 in and the ratio of lengths of its bases is 5:3. Find the lengths of the sides of
Natalka [10]
The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches

Let x = length of base and leg

The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base

       P = b₁ + b₂ + 2(leg)
     28 = 3x + 5x + 2(x)
     28 = 8x + 2x
28/10 = 10x/10
    2.8 = x

Now, substitute the values:
       P = b₁ + b₂ + 2(leg)
     28 = 3(2.8) + 5(2.8) + 2(2.8)
     28 = 8.4 + 14 + 5.6
     28 = 28

Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
8 0
3 years ago
Trig: Which complex number's graph is shown?
Andrei [34K]

ANSWER

2 \sqrt{2} ( \cos( \frac{7\pi}{4}   + i  \sin(  \frac{7\pi}{4} ) )

EXPLANATION

The complex number shown has coordinates (2,-2)

or

z = 2 - 2i

The modulus is

|z|  =  \sqrt{ {2}^{2}  +  {( - 2)}^{2} }

|z|  =  \sqrt{ 8} = 2 \sqrt{2}

The argument is

\theta= \tan^{ - 1} ( \frac{ - 2}{2} )

\theta= \tan^{ - 1} ( -1) =  \frac{7\pi}{4}

The polar form is

2 \sqrt{2} ( \cos( \frac{7\pi}{4}   + i  \sin(  \frac{7\pi}{4} ) )

The first option is correct.

3 0
3 years ago
Estimate ∫20(4x2−2x)dx= using a left Reimann Summ and 4 equal subintervals.
dolphi86 [110]

nice day folks eeeeeeeeeeeeeeeee

3 0
3 years ago
Find the focus of the parabola whose vertex is at<br> the origin and whose directrix is x = 3.
defon

Answer:

Step-by-step explanation:

Vertex is halfway between focus and directrix, so focus is (-3,0).

6 0
2 years ago
What is the distance BC between the two horizontal parallel bars?
pochemuha
One thing you should notice is that the transverse line and the parallel line form a right triangle. We are told that the base is 4 and the angle between the hypotenuse and the leg is 45°

From this we can solve for the second leg. Here's the list of trig functions

sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent

Since we are only given the adjacent and we are trying to solve for the opposite leg, we can deduce we use tanФ. So we get

tan45 = x/4

Multiply by 4 to isolate x and we get

4*tan45 = x
Hopes this helps!
8 0
2 years ago
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