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3 years ago

What is the greatest common factor of 24s3, 12s4, and 18s?

Mathematics

1 answer:

slava [35]3 years ago

7 0

Answer:

Step-by-step explanation:

The GCF if 24s^3, 12s^4 and 18s is

24s^3: 2^3 * 3 s s s

12s^4: 2^2 * 3 s *s* s* s

18s: 3^2 * 2 s

3s is the GCF

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3 years ago

The area of a rectangle is 70 m², and the length of the rectangle is 11 m less than three times the width. Find the dimensions o

11111nata11111 [884]

Step-by-step explanation:

the area of a rectangle is

length × width

in our case

length × width = 70 m²

length = 3×width - 11

we can use this second equation in the first and get

(3×width - 11) × width = 70

3×width² - 11×width - 70 = 0

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -11

c = -70

x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =

= (11 ± sqrt(121 + 840))/6 =

= (11 ± sqrt(961))/6

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x2 = (11 - 31)/6 = -20/6 = -10/3

the negative solution is not applicable for a length in an object.

so, only x1 = 7 m is our solution.

the width of the rectangle is 7 m.

the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m

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2 years ago