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Verizon [17]
3 years ago
13

C divided by 5 ? please i need help

Mathematics
1 answer:
KiRa [710]3 years ago
4 0

Answer:

0.2 coulombs is the answer

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-7/10+7/15+1/-20+-9/10+11/15+11/-20 <br> what is the answer please help me .....!!!!
Nat2105 [25]

Answer:

-1

Step-by-step explanation:

-7/10+7/15+1/-20+-9/10+11/15+11/-20

= -7/10 + -9/10 + 7/15 + 11/15 + 1/-20 + 11/-20

= -16/10 + 18/15 + 12/-20

= -8/5 + 6/5 + -3/5

= (-8+6-3)/5

= -5/5

= -1

7 0
3 years ago
Write a rule for each arithmetic sequence -3, -0.5, 2, 4.5,....
aivan3 [116]
The rule is add 2.5!!
3 0
3 years ago
Solve for x <br> x over 7 = 6
Karo-lina-s [1.5K]

Answer:

X = 42

Step-by-step explanation:

What divided by 7 equals 6..... 42! to prove we are right let us plug it into our equation.

42 / 7 = 6

DING DING DING Correct !

7 0
2 years ago
Read 2 more answers
What is this question in simplified form
EastWind [94]

Answer: -77\sqrt{30}

Step-by-step explanation:

(-7(3)^1/2)(11(10)^1/2)=

-7*11*(3)^1/2 * (10)^1/2=

-77*(3*10)^1/2=

-77(30)^1/2=-77\sqrt{30}

6 0
1 year ago
Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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