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Crazy boy [7]
2 years ago
9

Evaluate the expression: -a^2 + c(a-c) - n^2 a= -3 c= -2 n= 3

Mathematics
1 answer:
Travka [436]2 years ago
7 0

Answer: -a^2+c\left(a-c\right)-n^2a=3\quad :\quad c=-\frac{-a+\sqrt{-3a^2-4an^2-12}}{2},\:c=-\frac{-a-\sqrt{-3a^2-4an^2-12}}{2}

Step-by-step explanation: YW! plese mark branlest!

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Ok so assuming that the 'x' means multiply and not 'x' as in placeolder we do

PEMDAS
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exponents
multipilcation or division
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parethasees simplify first
(8+7)=15


(9-3)=6

now we have
2x(15)-6/2x(6)
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6/2x6=36/2=18

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Answer:

Givens:

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  • \angle C \cong \angle F

Using this information we could recur to SAS postulate to demonstrate the congruence of this pair of triangles. We already have one side and one angle congruent, we just need to demonstrate that AC \cong DF, that will prove the complete congruence.

So, based on the given coordinates, we're able to calculate the length of each side and find if they are the same. We use this formula:

d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\d_{AC} =\sqrt{(0-(-2))^{2}+(3-2)^{2}}=\sqrt{4+1}=\sqrt{5}\\\\\d_{DF} =\sqrt{(0-2)^{2}+(2-1)^{2}}=\sqrt{4+1}=\sqrt{5}

Therefore, AC \cong DF, because they have the same length.

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