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1 year ago

Evaluate the expression: -a^2 + c(a-c) - n^2 a= -3 c= -2 n= 3

Mathematics

1 answer:

Travka [436]1 year ago

7 0

Answer: -a^2+c\left(a-c\right)-n^2a=3\quad :\quad c=-\frac{-a+\sqrt{-3a^2-4an^2-12}}{2},\:c=-\frac{-a-\sqrt{-3a^2-4an^2-12}}{2}

Step-by-step explanation: YW! plese mark branlest!

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drek231 [11]

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3 years ago

a boat going upstream at 4 mph then travels downstream at 10 mph. what is the rate of the boat in still water

elixir [45]

Answer:

7 mph

Step-by-step explanation:

If b is the rate of the boat, and s is the rate of the stream, then:

b − s = 4

b + s = 10

Solve the system of equations with substitution or elimination. Using elimination, add the equations together:

2b = 14

b = 7

The boat's rate is 7 mph.

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3 years ago

A rectangular flowerbed at a city park has an area of 126 square meters.the width of the flowerbed is 3 meters.what is the perim

Alona [7]

First we need to find the length. So we do 126/3 to get 42. The length is 42. Now to find perimeter we do 2(42)+2(3) or 42+42+3+3.

Both ways are right ways. The perimeter is 90 meters.

Hope that helps!!

6 0

3 years ago

What is the slope of a line which is perpendicular to the line that has an equation of

nasty-shy [4]

First convert the equation in the form of y= mx + c

The equation will be like = y = 6x-5

value of m = 6

The slope of perpendicular line will be = -1/m = -1/6

4 0

3 years ago

Douglas invests money in two simple interest accounts. He invests three times as much in an account paying 14% as he does in an

Rainbow [258]

Douglas invested $ 1300 altogether

Solution:

Let x represent the amount invested in the account paying 14% interest.

Let y represent the amount invested in the account paying 5% interest

He invests three times as much in an account paying 14% as he does in an account paying 5%

Which means,

x = 3y

The simple interest is given by formula:

$S.I = \frac{p \times n \times r}{100}$

Where,

"p" is the principal

"n" is the number of years

"r" is the rate of interest

He earns $152.75 in interest in one year from both accounts combined

Therefore,

Combined S.I = 152.75

n = 1 year

Considering the account earning 14% interest:

$S.I = \frac{3y \times 14 \times 1}{100}\\\\S.I = 0.42y$

Considering the account earning 5% interest:

$S.I = \frac{y \times 5 \times 1}{100}\\\\S.I = 0.05y$

Since, Combined S.I = 152.75

Therefore,

0.42y + 0.05y = 152.75

0.47y = 152.75

Divide both sides by 0.47

y = 325

Therefore,

x = 3y

x = 3(325)

x = 975

how much did he invest altogether?

Amount invested together = x + y = 975 + 325 = 1300

Thus he invested $ 1300 altogether

3 0

2 years ago