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2 years ago

Someone please help me! i will mark brainliest if i can

Mathematics

1 answer:

dedylja [7]2 years ago

4 0

Answer: 19.8x - 11.1y

Step-by-step explanation: you’re welcome:)

Again lol

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Plz show ur work! Ty if u do. Will give brainilest!

Sati [7]

Answer:

12/32 divide by 4 and get 3/8 you can’t simplify any further after that

Step-by-step explanation:

5 0

3 years ago

. Asking 100 students at a large university for their opinions on campus life is an example of measuring a _____.

Slav-nsk [51]

Answer:

Step-by-step explanation:

I am assuming that the university has much more than 100 students so 100 people is just a small sample.

3 0

3 years ago

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PLEASE HELP!! 20 POINTS!! paul us getting a new bike, He can get either a racing bike or a mountain bike. His color choices are

serg [7]

Answer:

6 possible outcomes, 50% or 3/6 getting the racing bike, 2/6 or 1/3 being red, and 2/6 or 1/3 getting silver bike.

Step-by-step explanation:

racing bike mountain bike

red black silver red black silver

3 0

3 years ago

Mike began with $20 in savings and increased his savings by $10 every month. Lindsay began with $5 in savings and doubled her sa

MrMuchimi

Answer:

Lindsay...................................

3 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

Read 2 more answers