Answer:
36 millimeters
Step-by-step explanation:
From Pythagoras theorem, the square of the hypotenuse is equal to the sum of the square of the two other legs
In mathematical terms;
a^2 = b^2 + c^2
Let a represent the hypotenuse = 39 mm and the length of one leg, say c, is 15 mm
Slotting in the values of a and b
39^2 = b^2 + 15^2
1521 = b^2 + 225
collect like terms
1521 - 225 = b^2
1296 = b^2
Take the square root of both sides
36 = b
Therefore b = 36 mm
Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are

The volume of the box is equal to


so

simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A

solve for y

Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x

therefore
The original length was 41 inches and the original width was 16 inches
Less by far because 3.5 cups would be less than half
The answer is five because if you go for -3 that’s one in 8-6 is two and if you add one and three that’s for sure the only one you need is five and that would be just make no sense at all