Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Solve for x
so assuming that the fractions are
(9/4)-(1/*2x))=4/x then
get all x on one side
add 1/(2x) to both sides
9/4=(4/x)+(1/(2x))
make common denomators with x and 2x
common denomenator is 2x
4/x times 2/2=8/(2x)
9/4=8/(2x)+1/(2x)
add
9/4=9/(2x)
make common denomators with 4 and 2x
common denomator is 4x
9/4 times x/x=9x/(4x)
9/(2x) times 2/2=18/(4x)
9x/(4x)=18/(4x)
multiply both sides by 4x to clear fraction
9x=18
divide both sides by 9
x=2
Let x be the price of the breakfast.
We know that 20 percent of x is 1.80
Let's write this as a mathematical equation
0.2 x = 1.8
Let's divide both sides by 0.2 to isolate the x
x = 1.8 / 0.2
= 9
The price of the breakfast was $9.
Have an awesome day! :)
Answer:
im gonna say 40 in
Step-by-step explanation:
