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Ivan
3 years ago
10

CAN SOMEONE HELP ME PLSSSS !!!!!!

Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

Answer:B

Step-by-step explanation:

Hitman42 [59]3 years ago
6 0

Answer:

5 {g}^{2}  - 11 {g}^{}  + 8

Step-by-step explanation:

this \: is \: your \: answer \: ie \: option \: b \\ hope \: it \: helps \\ need \: thanks \: and \: brainliest...

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What is the answer to the equation 0.6x+1.3x=3.04
amm1812

Answer:

x = 1.6

Step-by-step explanation:

0.6x + 1.3x = 3.04

1.9x = 3.04

x = 3.04/1.9

x = 1.6

8 0
3 years ago
Read 2 more answers
The radius of the hydrogen atom is 0.529x10/-10 and the radius of the nucleus is 1.2x10/-15m. Compare the radius of each by writ
raketka [301]

we know that

The radius of the hydrogen atom is  0.529*10^{-10}m

The radius of the nucleus is  1.2*10^{-15}m

the ratio is equal to

\frac{0.529*10^{-10}}{ 1.2*10^{-15}} = 44,083.33

that means the radius of the hydrogen atom is 44,083.33 times the radius of the nucleus

therefore

<u>the answer is</u>

the ratio is equal to 44,083.33

7 0
3 years ago
Factor out the coefficient of the variable 1/4d-3/4
qwelly [4]
D/4 - 3/4
I don’t know for sure though
5 0
3 years ago
What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
This don’t make no sense anyone understand and if u do help plz
Bingel [31]

1. x = 0 and y = 3

2. x = 2 and y = 7

3. x = 3 and y = 9

4. x = 5 and y = 13

7 0
3 years ago
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