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4 years ago

PLEASE HELP ME ASAP I WILL MARK BRAINLIEST AND THANK AND 5 STARS

Mathematics

2 answers:

777dan777 [17]4 years ago

8 0

From the diagram above,

the image D was reflected

and that reflection was

reflection is reflection on the line

x =0 or reflection on the y-axis

From reflection on the y-axis

we use the expression

( x,y )____ ( -x, y ).

so when you check from the diagram, it's only image D which is in the negative x , positive y plane.

this means that image D was reflected on the line x=0

bearhunter [10]4 years ago

4 0

Answer:

Step-by-step explanation:

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Brianna's teacher asks her which of these three expressions are equivalent to each other. which is equivalent

docker41 [41]

Answer:

Please specify what the three expressions are.

Step-by-step explanation:

From what I understand, you need to set the expressions equal to each other. For instance, if one is 2(x-3) and the other is 2x-6, you could write it as:

$2(x-3)=2x-6$

Then, by evaluating it, you would get:

$2x-6=2x-6$ by distribution over subtraction.

$2x-6+6=2x-6+6$ by the additive property of equality

$2x=2x$ Simplify.

$x=x$ by the reflexive axiom.

Since x will always equal itself, 2(x-3) and 2x-6 are equivalent.

Therefore, if the expressions, once set equal to each other, result in the equation x=x, or any other expression in which one quantity equals itself, the two expressions are equal.

Sorry I could not be of more help, but you did not specify what the expressions were.

4 0

3 years ago

In how many unique ways can the seven letters in the word MINIMUM be arranged, if all the letters are used each time

slega [8]

The number of unique ways or permuations to arrange the seven letters in MINIMUM is all the letters are used each time is 420.

According to the given question.

We have a word MINIMUM.

Here, there are 7 letters in "MINIMUM" .

Now, in Minimum the number of letters which are repeated and which are not.

M = 3 times

I = 2 times

N = 1 time

U = 1 time

As, we all know if there is no repetitions in a word which is made of n letters, then we can arrange it by n! ways.

But if there is repetition, we use formula

$\frac{n!}{n_{1}! n_{2}!..n_{k}! }$

where, n = $n_{1} +n_{2} +n_{3} ...+n_{k}$

$n_{1}$ is objects of one type

$n_{2}$ is the objects of two types

$n_{k}$ is the objects of k types

Thereofore, the number of unique ways or permuations to arrange the seven letters in MINIMUM is all the letters are used each time

= 7!/ 3!2!

= 7(6)(5)(4)(3!)/3!(2)(1)

= 7(3)(5)(4)

= 420

Hence, the number of unique ways or permuations to arrange the seven letters in MINIMUM is all the letters are used each time is 420.

Find out more information about number of ways and permuations here:

brainly.com/question/15609044

#SPJ4

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1 year ago

Simplify -1/2x+3-4x+5+3/2x

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

-1/2x+3-4x+5+3/2x

=-1/2x+3/2x-4x+3+5

=x-4x+8

=-3x+8

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3 years ago

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3 years ago

Find the length of the missing side

timurjin [86]

Answer:

Step-by-step explanation:

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3 years ago

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